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shepuryov [24]
2 years ago
13

19 + 11 - 12² ÷ 3 (12 - 9) · 11)) - 7 =

Mathematics
1 answer:
katovenus [111]2 years ago
7 0

PEMDAS = Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

First, subtract the numbers in the parentheses, then multiply by 11.

(12 - 9) = (3)

3 x 11 = 33

19 + 11 - 12^2 ÷ 3(33) - 7

Now, just multiply 33 by 3, and then square 12 (12 x 12).

19 + 11 - 144 ÷ 99 - 7

Now, you can divide 144 by 99, this is an infinite number, so..

144 ÷ 99 = 1.455

19 + 11 - 1.455 - 7

Finally add, then subtract.

30 - 1.455 - 7

28.545 - 7

The final answer is 21.545.

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PLEASE HELP.! <br> Solve for k.<br><br> 2 = k/3<br> k = ?
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Answer:

6

Step-by-step explanation:

Because 6/3 equals 2

5 0
2 years ago
Read 2 more answers
For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in
Rainbow [258]

Answer:

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}  \begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}

Generally the echelon reduction is mathematically applied as

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -2 times the 1st row to the 2nd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}

Multiply the 2nd row by -1/8  

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -1 times the 2nd row to the 3rd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}

Multiply the 3rd row by -8/41

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -3 times the 2nd row to the 1st row

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

3 0
2 years ago
What is the value of 15/124•230/30 divided by 230/124
suter [353]
Okay, the first thing to do is to make it so you're multiplying everything instead of dividing by that last fraction. To divide by a fraction, you just multiply by its reciprocal. So then, it's 15/124 x 230/30 x 124/230. After that, let's organize it into one single giant fraction since order of operations allows us to arrange division and multiplication however we want. Then it's 15x230x124 / 124x30x230. Then, you'll notice that the 230s and 124s can both be canceled out, leaving 15/30. After simplifying, your final answer is 1/2.

3 0
3 years ago
The manager of a theater noted that for every 10 admission tickets sold, the theater sells 3 bags of popcorn at $2.25 each, 4 so
Shalnov [3]

Answer:

$1.475 is the average amount of snack sales per ticket sold.

Step-by-step explanation:

We are given the following in the question:

Number of popcorn bags sold = 3

Cost of  a popcorn bag = $2.25

Total cost of popcorn bag = 2.25\times 3 = $6.75

Number of soda sold = 4

Cost of  a soda = $1.50

Total cost of soda = 1.50\times 4 = $6.00

Number of candy bars sold = 2

Cost of  a candy bar = $1.00

Total cost of candy bars =  1.00\times 2 = $2.00

Total sales =

Total cost of popcorn + Total cost of soda + Total cost of candy bar

= 6.75 + 6 + 2\\=\$14.75

\text{Average} = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Average amount of snack sales per ticket sold =

\dfrac{\text{Total sales}}{\text{Number of tickets}} = \dfrac{14.75}{10} = 1.475

Thus, $1.475 is the average amount of snack sales per ticket sold.

5 0
2 years ago
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