Ask question

Ask question

All categories

3 years ago

15

Drew D. Dingaling came to Miraculous with a problem. Drew was told to measure 50 cm of copper wire to use in an experiment. Sinc

e his ruler only measured to 45 cm he used this amount of wire and his experiment was a failure. What was his percent error?

2 answers:

SVEN [57.7K]3 years ago

4 0

Answer:

the answer is 10% error.

hope this helps !

uysha [10]3 years ago

4 0

Answer:

spanich plis an español

You might be interested in

Thanks to all those who support my question!

Mazyrski [523]

Answer:

no, because intergers are negative. they will never be able to be greater

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The math club makes 35 bars of laundry soap a week and sells these at $20 each before the soap could be sold , the pupils found

Svet_ta [14]

Answer:

Step-by-step explanation:

The math club makes 35 bars of laundry soap a week and sells these at $20 each. This means that the total number of bars of laundry soap made in a 4 week month would be

4 × 35 = 140 bars

If the pupils found that 6 bars were destroyed by mice, the total number of bars of soap left would be

140 - 6 = 134 bars

Therefore, the total sale at the end of a four week month would be

134 × 20 = $2680

7 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

19 x 50 =_fifties. Please help me

ivanzaharov [21]

Nine hundred and fifty

3 0

2 years ago

Read 2 more answers

How much does 60% out of 100

Salsk061 [2.6K]

Answer:

60

Step-by-step explanation:

Given: 60% out of 100

Expressed mathematically:

= (60/100) x 100

= 60

3 0

3 years ago