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olganol [36]
3 years ago
7

What does x equal in this linear equation

Mathematics
2 answers:
sineoko [7]3 years ago
7 0
First you want to cross multiply. 2x+5 * 18 = 36x+90 and x * 6 = 6x. so then you would have 6x = 36x+90. now you want to sinplify. subtract 36x from both sides and you get -30x = 90. divide by -30 to get x to stand alone. x = -3
maw [93]3 years ago
3 0
6x=18 (2x+5) x=6x+15. x-15=6x 5x=15 x=3
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The lines shown below are perpendicular. If the green line has a slop of 2/5, what is the slope of the red line?
aivan3 [116]

The slope of the red line that is perpendicular to the green line is: -5/2.

<h3>What are the Slope Values of Perpendicular Lines?</h3>

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

<h3>What is the Negative Reciprocal of a Number?</h3>

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

Learn more about slope of perpendicular lines on:

brainly.com/question/1362601

#SPJ1

5 0
1 year ago
I WILL MAKE YOU BRAINIST
nekit [7.7K]

Answer:

234

Step-by-step explanation:

We want to find the summation from n = 2 to n = 10 of the equation -4 + 5n.

We can use the summation formula:

S=\frac{(a_1+a_n)*n}{2}, where a1 is the first term, a_n is the last term, and n is the number of terms

Here, we can say the first term occurs when n = 2:

-4 + 5n

-4 + 5 * 2 = -4 + 10 = 6

The last term will be when n = 10:

-4 + 5n

-4 + 5 * 10 = -4 + 50 = 46

The number of terms is just 10 - 2 + 1 = 9 terms.

Substitute these in:

S=\frac{(a_1+a_n)*n}{2}

S=\frac{(6+46)*9}{2}=\frac{468}{2} =234

Thus, the answer is 234.

8 0
3 years ago
Find the parametric equations for the line that is tangent to the given curve at the given parameter (3cost)i (t^4 -3sint)j
ale4655 [162]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

In the given equation, when the point t=0

So,

\to r(0) = (3 \cos 0)i + (0^4 - 6 \sin 0)j + (2e^{3\times 0})k)

           = (3 \times 1)i + (0 - 0)j + (2e^{0})k)\\\\ = 3i +  0j + (2 \times 1)k)\\\\ = 3i +  0j + 2k \\

The value of the coordinates are 3, 0, 2 . so, the equation of the line is:

\to \frac{(x-3)}{3 \cos \ t} = \frac{(y-0)}{(t^{4}-6 \sin \ t)} = \frac{(z-2)}{2e^{3t}}=k

5 0
3 years ago
In Store A, you can buy 3 notebooks
PolarNik [594]

Answer:

The price of one notebook is 2$

Step-by-step explanation:

3x + 2= 4x

Take x to the same side —> 4x-3x=2 —> x=2

3 0
3 years ago
There are 20 chocolate candies in a bag.
Eduardwww [97]

Answer:

A

Step-by-step explanation:

20/20 X 100 = 100%

have a good day

3 0
2 years ago
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