One number is 10 more than another. The sum of twice the smaller plus three times the larger, is 55. What are the two numbers?
1 answer:
Answer:
x(smaller)=4, y(bigger)=5
Step-by-step explanation:
(2x+3)*y=55
11*5=55
so, 2x+3=11
2x=8 after subtracting 3 from both sides
x=4 after dividing by 2 from both sides
y is then equal to 5 because 11y=55
divide both sides by 11, you get y=5, which means y>x, and y is the larger number.
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Answer:
3 a 20 - class yoga package for 260$
Answer:
x > 6
Step-by-step explanation:
Given
3x + 10 > 28 ( subtract 10 from both sides )
3x > 18 ( divide both sides by 3 )
x > 6
F-1:
y=x+9
y-9=x
x-9=f-1
f-1(14)=14-9=5 f-1(5)=5-9=-4 f-1(-5)=-5-9=-14 f-1(25)=25-9=16
f(14)=14+9=24 f(5)=5+9=14 f(-5)=9-5=4 f(25)=25+9=34
600,000 + 3,800 = 603,800
I’m not sure maybe if there was an imagine I’d be able to answer this question.