As a beam of light travels from one medium to another, the change in direction of the beam of light depends on

Physics

1 answer:

vladimir1956 [14]3 years ago

6 0

It depends on the substance of which the medium is made, whether it be gas, liquid, solid (or plasma)

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The forces F 1, F 2, ..., F n acting at the same point P are said to be in equilibrium if the resultant force is zero, that is,

allochka39001 [22]

For the forces to be in equilibrium:
F 1 + F 2 + F 3 + F 4 = 0
i + j + i - j + 9 i + 2 j + F 4 = 0
11 i + 2 j + F 4 = 0
F 4 = - 11 i + 2 j
F 4 = ( -11, - 2 )

5 0

3 years ago

Read 2 more answers

The formula v = √2.5r models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radiu

mel-nik [20]

Answer:

The maximum safe speed of the car is 30.82 m/s.

Explanation:

It is given that,

The formula that models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radius of curvature r r, is in feet is given by :

$v=\sqrt{2.5\ r}$ .........(1)

A highway crew measures the radius of curvature at an exit ramp on a highway as 380 feet, r = 380 feet

Put the value of r in equation (1) as :

$v=\sqrt{2.5\ \times 380}$

v = 30.82 m/s

So, the maximum safe speed of the car is 30.82 m/s. Hence, this is the required solution.

4 0

3 years ago

If Two stars, Betty and Wilma, are both on the main sequence. Betty is more luminous than Wilma. Which one has a hotter surface

monitta

Answer:

Betty

Explanation:

Since they're both on the most sequence but Betty is more luminous than Wilma, Betty must be located to a higher place on the most sequence. Therefore, Betty encompasses a hotter surface temperature, is more massive, and encompasses a larger radius. Betty also will evolve faster than Wilma, and if they were formed at the identical time Betty will put off the most sequence first

5 0

3 years ago

Help please!

Sloan [31]

Answer:

The will hit the ground in t = 0.51[sg] and he was moving with a velocity of 1.45 [m/s]

Explanation:

In the attached image, we can see a sketch of the conditions of the problem, we are interested to know how long the cat takes to fall from the table to the ground and then using that time we can find the initial velocity of the cat when it arrives at the edge of the table.

The initial condition of this problem is that when the cat reaches the edge of the table, it will only have initial velocity on the X-axis component, its velocity on the y-axis component will be zero.

Therefore:

$y=(v_{y})_{0}$

In this way, we can use the following equation of kinematics and find the time t.

$y=(v_{y})_{0}*t - \frac{1}{2} * g*t\\where:\\g =9.81[m/s^{2} ] gravity\\y = 1.3 [m] table height$ =0[/tex]

We note that gravity is taken as a negative quantity since the movement is downwards, likewise the value and the equation will have negative value as the reference point will be taken as the edge of the table, therefore, y = -1.3 [m]

$-1.3 = (0)*t - \frac{1}{2} * (9.81)*t^{2} \\t = \sqrt{\frac{2*1.3}{9.81} }\\ t= 0.51 [m/s]\\$