First, you find what 20% of 10 gallons of gas would be. This will show how many gallons the car actually uses.
10 gallons x 20% =
10 x 0.20 =
2 gallons used
Then you subtract that number from the total 10 gallons to get how many gallons of gas would be wasted.
10 gallons - 2 gallons =
8 gallons of gas wasted
Answer:
Trial 1 is the largest, trial 3 is the smallest
Explanation:
Given:
<em>Trial 1</em>
M₁ = 6·10²² kg
d₁ = 3 500 km = 3.5·10⁶ м
<em>Trial 2</em>
M₂ = 6·10²² kg
d₂ = 7 000 km = 7·10⁶ м
<em>Trial 3</em>
M₃ = 3·10²² kg
d₃ = 7 000 km = 7·10⁶ м
___________
F - ?
Gravitational force:
F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m (N)
F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m (N)
F₃ = G·m·M₃ / d₃² = m·6.67·10⁻¹¹·3·10²² / (7·10⁶)² = 0.04·m (N)
Trial 1 is the largest, trial 3 is the smallest
Acceleration occurs whenever the direction or the speed changes
C. Cause your just standing in line holding a tray.
Answer:
Distance between two concentric circles is in radius d = 1.0 um
Explanation:
Given:
- Wavelength of light λ = 680 nm
- Distance of disc from screen x = 1.5 m
- Separation between central and first order y = 1.4 m
- Angle Q is between central order and mth order
Find:
What is the distance between the circles on the CD’s surface? - d?
Solution:
- The relationship between and wavelength and the position of fringes with respect to diffraction grating is given by Youns's experiment as follows:
sin (Q) = m*λ / d
- Compute the angle Q for first order m = 1:
sin(Q) = 1.4 / sqrt(1.4^2 + 1.5^2)
sin(Q) = 1.4 / 2.05183
sin(Q) = 0.68232
- Use the above result and compute for the grating d for m =1 :
d = λ / sin(Q)
d = 680*10^-9 / 0.68232
d = 1.0 um
- Since the circles are concentric the difference in radius is d = 1.0 um
