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3 years ago

I don’t know how to do question 3

Mathematics

1 answer:

antoniya [11.8K]3 years ago

5 0

Answer:

The function y = -x whose reflection in the line y =x is itself.

Step-by-step explanation:

A reflection that maps every point of a figure to an image across a fixed line. Then the fixed line is called the line of reflection.

The reflection of the point (x,y) in the line y = x is the point (y, x).

Therefore, the function y = -x whose reflection in the line y =x is itself.

Symmetries of the function f(x)= -x is:

A function symmetric with respect to the y-axis is called an even function.

If f(-x) = f(x)

A function that is symmetric with respect to the origin is called an odd function.

if f(-x) = -f(x)

then, we must look at f(-x);

f(x) = -x

f(-x)= -(-x)= x = -f(x)

this function is symmetrical to with respect to origin.

Therefore, this function is an odd function.

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Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

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Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

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Answer: B. The United States might not have been able to stop the attacks, but it could have made a better effort to do so.

Step-by-step explanation:

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3 years ago

The population of a certain species of fish in a lake has a relative growth rate of 1-2%. It is estimated the population in the

hichkok12 [17]

Answer:

Fish Population The population of a certain species of fish has a relative growth rate of 1.2 %per year. It is estimated that the population in 2000 was 12 million. (a) Find an exponential model for the population tyears after 2000 . (b) Estimate the fish population in the year 2005 (c) Sketch a graph of the fish population.

Step-by-step explanation: