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AnnyKZ [126]
3 years ago
11

Determine the intersepts of the lines ​

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

Y-intercept is (0, 100) and the X-intercept is (-250, 0)

Step-by-step explanation:

For the y-intercept the line from the origin does not move left or right and stays at 0 but it goes up by 100.

For the x-intercept the line does not go up and down but it goes to the left -250.

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After substituting, what is the first step when evaluating 4y+9/7 when y=8
kenny6666 [7]

Answer:

  multiply 4 and 8 to get 32

Step-by-step explanation:

After substituting, the expression is ...

  4·8 +9/7

The order of operations tells you to do multiplication and division before addition and subtraction. You do them left-to-right. The multiplication on the left is 4·8, so you do that first. The result is ...

  32 + 9/7

Now, you can do the division:

  32 + (1 2/7)

And, finally, the addition:

  33 2/7

___

Or, you could skip the division and go straight to adding a whole number and a fraction:

  (32·7 +9)/7 = (224+9)/7 = 233/7

7 0
4 years ago
Helps me pleaseeeeeee
exis [7]
There is no question...???
3 0
3 years ago
Fourth term of sequence is 216, sixth term 96
My name is Ann [436]
312 I think, hop[e this helps
4 0
3 years ago
Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac
Anestetic [448]

Answer:

Tacoma's population in 2014 will be 587,439 people

Step-by-step explanation:

we know that

The equation of a exponential growth function  is given by the formula

y=a(1+r)^x

where

y is Tacoma's population in thousand

x is the number of years since 2000

r is the rate of change

a is the initial value

we have

a=200\\r=8\%=8/100=0.08

substitute

y=200(1+0.08)^x

y=200(1.08)^x

what will Tacoma's population be in 2014?

Find the value of x

x=2014-2000=14\ years

substitute the value of x

y=200(1.08)^{14}=587.439\ thousand

therefore

Tacoma's population in 2014 will be 587,439 people

5 0
3 years ago
Can someone help on a construction of a tangent to a circle please, need pictures if possible
Anit [1.1K]

Wassup

Steps:

1. Draw a line connecting the point to the center of the rectangle

2. Then construct a perpendicular bisector to the line drawn in step 1

3. Place the compass on the midpoint of the line, adjust its length to reach the end point, and draw an arc across the circle

4. Where the arc crosses the circle will be the tangent points. So connect the endpoint to the tangent point

Hope the picture helps you too

5 0
3 years ago
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