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4 years ago

For every 15 students who run track, there are 7 students who play baseball. There are 112 more students

Mathematics

2 answers:

wolverine [178]4 years ago

4 0

Answer:

There are 210 students running track and 98 students that play baseball.

Step-by-step explanation:

15*14= 210 and 7*14 = 98, 210 - 98 = 112. If this was correct feel free to mark me as brainiest :)

Mandarinka [93]4 years ago

4 0

Answer:

There are 210 students who run track and 98 students who play baseball.

Step-by-step explanation:

It is important to approach the question this way; the students who play the two sports are grouped.

Let X be the number of groups. So that, from the question, we can deduce that;

There are 15 students in one group of those who run track and there are 7 students in each group of those who play baseball.

Total number of students who run track = 15 × X = 15X

Total number of students who play baseball = 7 × X = 7X

Now, the difference in the two total numbers is 112 as given in the question, so we can write that;

15X - 7X = 112

8X = 112

X = $\frac{112}{8}$ = 14

So,

Total number of students who run track = 15 × X = 15 × 14 = 210

Total number of students who play baseball = 7 × X = 7 × 14 = 98

There are 210 students who run track and 98 students who play baseball

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3 years ago

1. Find the digit that makes 3,71_ divisible by 9.

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QUESTION 1

We want to find the digit that should fill the blank space to make

$3,71-$

divisible by 9.

If a number is divisible by 9 then the sum of the digits should be a multiple of 9.

The sum of the given digits is,

$3 + 7 + 1 = 11$

Since

$11 + 7 = 18$

which is a multiple of 9.

This means that

$3,717$

is divisible by 9.

The correct answer is B

QUESTION 2

The factors of the number 30 are all the numbers that divides 30 exactly without a remainder.

These numbers are ;

$1,2,3,5,6,10,15,30$

The correct answer is A.

QUESTION 3.

We want to find the prime factorization of the number 168.

The prime numbers that are factors of 168 are

$2,3 \: and \: 7$

We can write 168 as the product of these three prime numbers to obtain,

$168={2}^{3}\times 3\times7$

We can also use the factor tree as shown in the attachment to write the prime factorization of 168 as

$168 ={2}^{3}\times 3\times7$

The correct answer is B.

QUESTION 4.

We want to find the greatest common factor of

$140\:\:and\:\:180$

We need to express each of these numbers as a product of prime factors.

The prime factorization of 140 is

$140={2}^{2}\times 5\times7.$

The prime factorization of 180 is

$180={2}^{2} \times{3}^{2}\times5.$

The greatest common factor is the product of the least degree of each common factor.

$GCF={2}^{2}\times5$

$GCF=20$

The correct answer is A.

QUESTION 5.

We want to find the greatest common factor of

$15,30\: and\:60.$

We need to first find the prime factorization of each number.

The prime factorization of 15 is

$15=3\times5.$

The prime factorization of 30 is

$30=2\times 3\times 5.$

The prime factorization of 60 is

$60={2}^{2}\times3 \times5$

The greatest common factor of these three numbers is the product of the factors with the least degree that is common to them.

$GCF=3 \times5$

$GCF=15$

The correct answer is C.

QUESTION 6

We want to determine which of the given fractions is equivalent to

$\frac{3}{8}.$

We must therefore simplify each option,

$A.\: \: \frac{15}{32}=\frac{15}{32}$

$B.\:\:\frac{12}{32}=\frac{4\times 3}{4\times8}=\frac{3}{8}$

$C.\:\:\:\:\frac{12}{24}=\frac{12\times1}{12\times 2}=\frac{1}{2}$

$D.\:\:\frac{9}{32}=\frac{9}{32}$

The simplification shows that

$\frac{12}{32}\equiv \frac{3}{8}$

The correct answer is B.

QUESTION 7.

We want to express

$\frac{10}{22}$

in the simplest form.

We just have to cancel out common factors as follows.

$\frac{10}{22}=\frac{2\times5}{2 \times11}$

This simplifies to,

$\frac{10}{22}=\frac{5}{11}$

The correct answer is C.

QUESTION 8.

We were given that Justin visited $25$ of the $50$ states.

The question requires that we express $25$ as a fraction of $50.$

This will give us

$\frac{25}{50}=\frac{25\times1}{25\times2}$

We must cancel out the common factors to have our fraction in the simplest form.

$\frac{25}{50}=\frac{1}{2}$

The correct answer is C.

QUESTION 9.

We want to write

$2\frac{5}{8}$

as an improper fraction.

We need to multiply the 2 by the denominator which is 8 and add the product to 5 and then express the result over 8.

This gives us,

$2 \frac{5}{8}=\frac{2\times8+5}{8}$

this implies that,

$2\frac{5}{8}=\frac{16+5}{8}$

$2\frac{5}{8}=\frac{21}{8}$

Sarah needed

$\frac{21}{8}\:\:yards$

The correct answer is D.

QUESTION 10

See attachment

QUESTION 11

We wan to write

$3\: and\:\:\frac{7}{8}$

as an improper fraction.

This implies that,

$3+\frac{7}{8}=3\frac{7}{8}$

To write this as a mixed number, we have,

$3\frac{7}{8}=\frac{3\times8+7}{8}$

This implies that,

$3\frac{7}{8}=\frac{24+7}{8}$

This gives

$3\frac{7}{8}=\frac{31}{8}$

The correct answer is B.

QUESTION 12

We want to find the LCM of $30$ and $46$ using prime factorization.

The prime factorization of 30 is $30=2\times 3\times 5$

The prime factorization of 46 is $40=2\times 23$ .

The LCM is the product of the common factors with the highest degrees. This gives us,

$LCM=2\times \times3 5\times 23$

$LCM=690$

The correct answer is D.

QUESTION 13

We want to find the least common multiple of 3,6 and 7.

The prime factorization of $3$ is $3$ .

The prime factorization of 6 is $6=2\times 3$ .

The prime factorization of 7 is $7$ .

The LCM is the product of the common factors with the highest degrees. This gives us,

$LCM=2\times3 \times7$

$LCM=42$ .

The LCM is 42, therefore 42 days will pass before all three bikes will at the park on the same day again.

The correct answer is B.

See attachment for continuation.

6 0

3 years ago

Read 2 more answers

Please help find the greatest common factor for these two problems

vekshin1

A greatest common factor is the largest number that goes into two or more numbers (in this case two). To find the GCF of two numbers, we have to find the prime factorization (how to express a number as a product of prime numbers) and then see which numbers are common in both of the prime factorizations.

13. The prime factorization of 8 is 2 * 2 * 2. The prime factorization of 26 is 2 * 13. Looking at the prime factorizations, we can see that both of them have 2. That means that the GCF is 1 * 2 which is 2.

12. The prime factorization of 105 is 3 * 5 * 7. The prime factorization of -30 is -5 * 6. We see that the number shared 5. That means that the GCF is 5 * 1 or 5.

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3 years ago

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jok3333 [9.3K]

Answer:

Step-by-step explanation:

Put the value where the variable is and do the arithmetic. It can save some steps to simplify the expression first.

35 -c³ +8 = 43 -c³

c = 1

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43 - 2³ = 43 -8 = 35

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43 -3³ = 43 -27 = 16

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Additional comment

It does not take long to learn how to use a spreadsheet for evaluating the same formula with a number of different values of the variable(s). Graphing calculators can do this, too. It is always appropriate to use the right tool for the job.

Familiarity with multiplication and addition facts is a very good place to start. It is also useful to memorize the squares and cubes of small integers. The latter are needed here.

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