1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leona [35]
3 years ago
15

For every 15 students who run track, there are 7 students who play baseball. There are 112 more students

Mathematics
2 answers:
wolverine [178]3 years ago
4 0

Answer:

There are 210 students running track and 98 students that play baseball.

Step-by-step explanation:

15*14= 210 and 7*14 = 98, 210 - 98 = 112. If this was correct feel free to mark me as brainiest :)

Mandarinka [93]3 years ago
4 0

Answer:

There are 210 students who run track and 98 students who play baseball.

Step-by-step explanation:

It is important to approach the question this way; the students who play the two sports are grouped.

Let X be the number of groups. So that, from the question, we can deduce that;

There are 15 students in one group of those who run track and there are 7 students in each group of those who play baseball.

Total number of students who run track = 15 × X = 15X

Total number of students who play baseball = 7 × X = 7X

Now, the difference in the two total numbers is 112 as given in the question, so we can write that;

15X - 7X = 112

8X = 112

X = \frac{112}{8} = 14

So,

Total number of students who run track = 15 × X = 15 × 14 = 210

Total number of students who play baseball = 7 × X = 7 × 14 = 98

There are 210 students who run track and 98 students who play baseball

You might be interested in
Calculate the total surface area of the triangular pyramid.
AleksandrR [38]

Answer:

45

Step-by-step explanation:

15+10= 25 + 20 = 45

3 0
2 years ago
Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp
yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

H_0: \mu=2\\\\H_a:\mu< 2

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803

The degrees of freedom for this sample size are:

df=n-1=52-1=51

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0
2 years ago
Given the sequence 8, 16, 32, 64, ..., which expression would give the thirteenth term?
mrs_skeptik [129]
8, 16, 32, 64,…
 ×2  ×2  ×2

a_{n} = a_{1} * r^{n - 1}
a_{n} = 8 * 2^{13 - 1}
a_{n} = 8 * 2^{12}
a_{n} = 8 * 4096
a_{n} = 32768

           First Term: 8
      Second Term: 16
          Third Term: 32
        Fourth Term: 64
           Fifth Term: 128
          Sixth Term: 256
     Seventh Term: 512
       Eighth Term: 1024
         Ninth Term: 2048
        Tenth Term: 4096
   Eleventh Term: 8192
     Twelfth Term: 16384
Thirteenth Term: 32768

The\ expression\ that\ would\ give\ the\ thirteenth\ term\ of\ the\ problem\ would\ be\ the\ equation\ of\ the\ geometric\ sequence,\ which\ is\ equal\ to\ a_{n} = a_{1} * r^{n - 1}.

5 0
3 years ago
Read 2 more answers
Olivia is making baggies of cookies for a bake sale. She wants to put nine cookies in each bag. She made 41 oatmeal cookies and
Rzqust [24]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
A machine produces defective parts with three different probabilities depending on its state of repair. If the machine is in goo
Zina [86]

Answer:

Step-by-step explanation:

Given that a machine produces defective parts with three different probabilities depending on its state of repair.

condition             Good order         Wearing down               Needs main   Total

Prob                       0.8                            0.1                                   0.1              1

Defective               0.02                          0.1                                   0.3

Joint prob              0.016                         0.01                                0.03        0.056

a) 0.016

b) total = 0.056

c) If not defective from needs maintenance

Prob for not defective = 0.8*0.98+0.1*0.9+0.1*0.7\\=0.784+0.09+0.07\\=0.944

From machine that needs maintenance = 0.07

So reqd prob = \frac{0.07}{0.944} \\=0.0741

6 0
3 years ago
Other questions:
  • A rectangle’s width is one-fourth of its length. Its area is 9 square units. The equation l(1/4l) = 9 can be used to find l, the
    8·2 answers
  • Solve the system of equations:<br> x+y=6 <br> 3x−5y=2
    12·1 answer
  • Answerrrrrrrr nowwww
    11·2 answers
  • There is a 85% chance that you will go to a Eagles concert given that the weather is good. If there is a 60% chance that the wea
    14·1 answer
  • For how long will the Tokyo Olympics be delayed?
    9·1 answer
  • Plssss help i give brainliest
    11·1 answer
  • Each big square below represents one whole.
    8·1 answer
  • What is the slope of the line that passes through these points in decimal form
    11·1 answer
  • Solve for x to the nearest tenth.
    14·1 answer
  • I need help solving this problem
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!