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Jobisdone [24]
3 years ago
12

Find the distance between the points (-3,- 2.2) and (-3,2.6).

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

<em>d = 4.8 units </em>

Step-by-step explanation:

( x_{1} , y_{1} )

( x_{2} , y_{2} )

d = \sqrt{(x_{2} -x_{1} )^2 + (y_{2} -y_{1} )^2}

~~~~~~~~~~~

( - 3, 2.6 )

( - 3, - 2.2 )

<em>d</em> = \sqrt{(-3+3)^2 +(-2.2-2.6)^2 } = √(- 4.8)² <em>= 4.8 units</em>

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Step-by-step explanation:

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4 years ago
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Step-by-step explanation:

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YEAR 3: 42436 X .03 = 1273.08    42436 + 1273.08 = 43709.08

YEAR 4: 43709.08 x .03 = 1311.27    43709.08 + 1311.27 = 45020.35

YEAR 5: 45020.35 X .03 = 1350.61    45020.35 + 1350.61 = 46370.96

YEAR 6: 46370.96 X .03 = 1391.13         46370.96 + 1391.13 = 47762.09

YEAR 7: 47762.09 X .03 = 1432.86       47762.09 + 1432.86 = 49194.95

YEAR 8: 49194.95 X .03 = 1475.85        49194.95 + 1475.85 = 50670.80

YEAR 9: 50670.80 X .03 =  1520.12         50670.80 + 1520.12 = 52190.92

YEAR 10: 52190.92 X .03 = 1565.73         52190.92 + 1565.73 = 53756.65

YEAR 11: 53756.65 X .03 = 1612.70             53756.65 + 1612.70 = 55369.35

YEAR 12: 55369.35 X .03 = 1661.08           55369.35 + 1661.08 = 57030.43

YEAR 13: 57030.43 X .03 = 1710.91            57030.43 + 1710.91 = 58741.34

YEAR 14: 58741.34 X .03 = 1762.24            58741.34 + 1762.24 = 60503.58

YEAR 15: 60503.58 X .03 = 1815.11           60503.58 + 1815.11 = 62318.69

YEAR 16: 62318.69 X .03 = 1869.56         62318.69 + 1869.56 = $64,188.25 = $64188

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