Question

Answer has to be in two significant figures

Answer 1

Answer: 2.186 m

Explanation:

formula for molality: (mol solute)/(kg solvent)

Na2CO3 = solute

510g Na2CO3 * ( 1 mol / 106 g) = 4.811 mol solute

ethylene glycol = solvent

2.2 * 10^3 g * ( 1 kg / 1000 g) = 2.2 kg

(4.811/2.2) = 2.186