All categories

3 years ago

No pure elements are liquids at room temperature.

Chemistry

1 answer:

Luden [163]3 years ago

8 0

Mercury and Bromine are liquid at room temperature.

You might be interested in

Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The

Maksim231197 [3]

Answer:

$\large\boxed{\large\boxed{24.6kJ}}$

Explanation:

1. Energy to heat the liquid water from 55ºC to 100ºC

$Q=m\times C\times \Delta T$

m = 10.1g

C = 4.18g/JºC

ΔT = 100ºC - 55ºC = 45ºC

$Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J$

2. Energy to change the liquid to steam at 100ºC

$L=\lambda \times n$

λ = 40.6kJ/mol

n = 10.1g / 18.015g/mol = 0.5606mol

$L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J$

3. Total energy

$1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ$

7 0

3 years ago

What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide

melomori [17]

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in $1.204\times 10^{24}$ molecules = $\frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}$

= 2 moles

therefore mass of sulfur dioxide = moles×atomic number

=2×(16+32)

=96

6 0

3 years ago

Newton believed _______ _______ were encoded alchemic recipes.

Zinaida [17]

I would say "Greek myths"

8 0

3 years ago

Read 2 more answers

One of these notations represents the definition of one mole. That is

just olya [345]

Answer:

6.02*10^23

Explanation:

This is the number for one mole. Just like one dozen = 12, one mole = 6.02*10^23.

Fun fact, if you had a mole of pennies you could spend 1 million dollars every second of your life and not have even spent 1% of it by the time you die at 100 years old.

3 0

4 years ago

Labels of many food products have expiration dates, at which point they are typically removed from the supermarket shelves. A pa

White raven [17]

Answer:

Explanation:

Since it first order, we use order rate equation

In ( $\frac{A1}{A0}$ ) = -kt where A1 is the final quality = 0.8 (80%), A0 is the initial quality = 1 ( 100%)