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Lady_Fox [76]
4 years ago
11

An aqueous solution at 27°c contains 3.6 g of a protein in a 200 ml sample. the osmotic pressure is 0.0203 atm. what is the mola

r mass of the protein
Chemistry
1 answer:
umka21 [38]4 years ago
8 0
In order to calculate the molar mass of the protein, we may manipulate the ideal gas equation:
PV = nRT, where n is the number of moles. We also know that:
n = m / Mr, where m is mass and Mr is molecular weight
Thus,
Mr = (mRT)/(PV)
Here, the mass is in grams, the temperature is in Kelvin, the pressure is in atm and the volume is in liters, so the molar gas constant is 0.082057.

Mr = (3.6 * 0.082057 * (27 + 273)) / (0.0203 * 0.2)
Mr = 21,828 g/mol
Thus, the Mr of the protein is 2.18 x 10⁴ g/mol
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<u>Answer:</u> The mass of water produced is 1.8 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

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Given mass of ethanol = 4.59 g

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Putting values in equation 1, we get:

\text{Moles of ethanol}=\frac{4.59g}{46.07g/mol}=0.0996mol

The chemical equation for the reaction of ethanol with oxygen gas follows:

CH_3CH_2OH+O_2\rightarrow CH_3COOH+H_2O

By Stoichiometry of the reaction;

1 mole of ethanol produces 1 mole of water.

So, 0.0996 moles of ethanol will produce = \frac{1}{1}\times 0.0996=0.0996mol of water.

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Molar mass of water = 18 g/mol

Moles of water = 0.0996 moles

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0.0996mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.0996mol\times 18g/mol)=1.8g

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