To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:
mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
Answer:
Reaction a: chemical, reaction b: nuclear
Explanation:
charge of elements increases by one as you move from left to right.
Answer:
Germanium.
Explanation:
In a neutral atom: the number of protons = the number of electrons.
Atomic number of a neutral atom = number of electrons = number of protons.
- Phosphorous is an element with atomic number 15 and thus contains 15 electrons and 15 protons.
- Cobalt is an element with atomic number 27 and thus contains 27 electrons and 27 protons.
- <em>Germanium is an element with atomic number 32 and thus contains 32 electrons and 32 protons.</em>
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- Sulfur is an element with atomic number 16 and thus contains 16 electrons and 16 protons.
Answer: 0.000625
Explanation:
If you don't know, one Milligram is equivalent to 0.000001 Kilograms. Hence, we'll multiply 625 by 0.000001.
With that being said, 625 times 0.000001 will equal to 0.000625.
Don't forget to add the units.
Milogram unit ⇒ mg
Kilogram unit ⇒ kg
Finally, your grand answer is 0.000625.
<em>Please comment down below for any questions about my answer.</em>
