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Lubov Fominskaja [6]
3 years ago
14

Tammy will rent a car for the weekend. She can choose one of two plans. The first plan has no initial fee but costs 0.70 per mil

e driven. The second plan has an initial fee of 65 and costs an additional 0.50 per mile driven. How many miles would Tammy need to drive for the two plans to cost the same?
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0
This problem is about linear equations. We assume Dale drive X miles, and the total cost is $Y, then we can get:
Plan I: Y=38+0.11X
Plan II: Y=49+0.07X
When both plans cost the same, 38+0.11X=49+0.07X. We will get X = 275miles, and Y=$68.25
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Write an equation of the line that passes through the points (2,−1) and (0,1).
Alina [70]
0,1 is the y-intercept 
5 0
4 years ago
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How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
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g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
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\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
8 0
3 years ago
Can someone help me with 1-142 all the way to 1-144??
mezya [45]

CL.1.142):

A):      

x5 ==>      4 boxes  =   3ft   <==== x5

20 boxes   =       ?  ft

20 boxes  is    15 ft. high



B):   x3  ===>   4 boxes     =    3ft.  <==== x3

   ?   boxes           =          9ft.

       12 boxes  will fit in one stack.



c):  CL.143

 Perimeter  =     15  +  29  +  9  +  11  +  6  +  18   =====>  88m

A1    =    b  *   h

(18)(15)  

270m^2


A2    =   b  *  h

(11)(9)

99

Total  Area ======>   270    +    99   ======>  369m^2









CL.1-144

1/4    +   1/4   +   1/5     =    5/20    +   5/20   +   4/20    ====>    14/20

1/4  *    5/5  =====>  5/20

1/5   *    4/4    =====>  4/20

14/20      +      ?/20       =      20/20

?      =       6  Missing    Section

6/20      ======>     3/10





CL-1.145

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0.4            ========>    40%



B):    1/6  ======>   .00000

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CL-1.146

ADD:   1/6   +   1/2   show all steps:

1/6   +   1/2

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Hope that helps!!!!                                   : )


5 0
3 years ago
A triangle's height is 10 feet more than its base. If the area of the triangle is 100 square feet, use factoring to find its dim
stiks02 [169]

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

Step-by-step explanation:

Height = base + 10

Area = 100 square ft

Area of a triangle= (1/2) (b) (h)

100 = (1/2) (b) (b + 10)

200 = b(b) + 10b

b(b) + 10b - 200 = 0

b(b) + 20b - 10b - 200 = 0

b ( b + 20) -10(b + 20) = 0

(b-10) (b+20) =0

b = 10 (or) b = -20

Here b is the length and cannot be negative.

So, b = 10ft

h = b + 10

h = 10 + 10

h = 20 ft.

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

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Zarrin [17]
$24.50*0.3 = $7.35
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