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2 years ago

What are the components of a proofs in proving that two triangle are congruent?

Mathematics

1 answer:

Alexxandr [17]2 years ago

8 0

Answer:

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Step-by-step explanation:

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A solid cylinder has a radius of 4.9 cm and a height of 3.5 cm. Work out the total surface area of the cylinder. Give your answe

Novosadov [1.4K]

Answer:

252 cm²

Step-by-step Explanation:

=>Given:

r = 4.9 cm, and h = 3.3 cm of a solid cylinder, π = 3.14

=> Required:

Total Surface Area (T.S.A) = 2πrh + 2πr²

T.S.A = 2*3.14*4.9*3.3 + 2*3.14*4.9²

= 101.5476 + 150.7828

= 252.3304

= 252 cm² (approximated)

8 0

2 years ago

Sketch a graph that is discrete, has a maximum, does not pass through the origin, and is an absolute value function

Stella [2.4K]

Um.. I can't sketch a graph on here.
A discrete function can't be an absolute value function because an absolute value function is continuous. But, the function equation can be as simple as
f(x) = - | x + 1 |
Just don't connect the dots when you draw it and boom, you're done.

6 0

2 years ago

3 + (6 x (11+1 -4)) ÷ 8 x 2

jolli1 [7]

Answer:

Three plus 6=9 times 11=99+1=100-4=96 divided by 8=12 times 2= 24

3 0

2 years ago

Read 2 more answers

Helppppppppp me please :(

MaRussiya [10]

Answer:

12.57cm

Step-by-step explanation:

circumference =2^r

=2×22/7×2

=12.57cm

8 0

2 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago