Use cosine rule,
cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)
cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)
cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)
Check:29.926+56.251+93.823=180.0 degrees....ok
Answer:
P(t) = 282.2(1.009)^t
Step-by-step explanation:
Look at the attached image.
Hope you can read my handwriting. the image cut off the right side, b = 1.009213324... but question asks to round to nearest thousandth so it's 1.009
For the second part just use the equation to find P when t = -1 and see if P is less than (underpredicts) the number from the question or greater than (overpredicts) the number. I haven't calculated it but I think it will be smaller and thus underpredicts just from looking at the numbers when t = -1
Answer:
a graph can be divided into 4 quadrants.
a zero abscissa, means the point lies on the origin.
a negative ordinate means the point lies on the y axis in the third and fourth quadrants.
You will factor out the common factor of t if you are solving for t. you will then divide both sides by (s+3) to make t the subject of the formula. for this question you can only get t in terms of s.
so:
st+3t=6
t(s+3)/(s+3)=6/(s+3)
t=6/(s+3)
if you are required to solve for s then you are going to subtract 3t from both sides. you can factorise 6-3t .you will then divide both sides by t to isolate s.for this question you can only get s in terms of t.so:
st+3t-3t=6-3t
st/t=2(3-t)/t
s=2(3-t)/t
Answer:
an = 88+9
Step-by-step explanation: