Question

Two cars leave towns 800 kilometers apart at the same time and travel toward each other. One car's rate is 18 kilometers per hour less than the other's. If they meet in 5 hours, what is the rate of the slower car?

Answer 1

Answer:

speed of slower car is 71 km/h

Explanation:

The distance between two cars is given as

$d = 800 km$

time taken by two cars to meet is given as

$t = 5 hours$

now the relative speed of two cars is given as

$v_{rel} = \frac{d}{t}$

$v_1 + v_2 = \frac{800}{5} = 160 km/h$

also it is given that the difference of speed of two cars is

$v_1 - v_2 = 18 km/h$

now from above two equations we have

$v_1 = 89 km/h$

$v_2 = 71 km/h$