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3 years ago

Which nucleus complete the following equation

Physics

1 answer:

rosijanka [135]3 years ago

7 0

Explanation:

$^{212}_{86}\text{Rn} \rightarrow \:^4_2\text{He} + \:^{208}_{84}\text{Po}$

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If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h

raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory ( $u_x$ ) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

$u^2=u_x^2+u_y^2$

Where, $u_x\ and\ u_y$ are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

$(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1$

Now, we know that, for a projectile motion, the maximum height is given as:

$H=\frac{u_y^2}{2g}$

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

$H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m$

Therefore, the maximum height reached is 4.63 m.

3 0

4 years ago

What type of bulb is unaffected

emmasim [6.3K]

c) Parallel

Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.

3 0

2 years ago

an airplane drops a 100 kg package of supplies for a town in need. the airplane is flying 600 m above the ground. What is the ac

makkiz [27]

Explanation:

Assuming no air resistance, the package accelerates at 9.8 m/s² towards the Earth.

7 0

4 years ago

Is work done when falling towards earth while skydiving???

GuDViN [60]

You betcha !

-- Work is done whenever a force acts through a distance.

-- The skydiver has weight. That's the force acting on him.

-- As time goes on, I'm assuming that he falls from one height
to a lower height. That's the distance the force acts through.

-- The work done on him is (force) times (distance)

(his weight) x (distance he falls).

So where is the machine that does all this work ?

-- It's GRAVITY that does the work on him as he falls.

So how did he get all this energy in the first place ?
Where did it come from ?

-- From the airplane that lifted him up to height from which he jumped !

3 0

3 years ago

Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente

yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

$v=\lambda f$ (1)

v: speed of the wave = 1,97 m/s

λ: wavelength

f: frequency of the wave = 0,07 Hz

You replace the values of v and f in the equation (1) and solve for λ:

$\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m$

hence, the wavelength of the wave is 28,14 m

5 0

3 years ago