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Arlecino [84]
4 years ago
5

A toy car moves around a circular track at constant speed. It suddenly doubles its speed — a change of a factor of 2. As a resul

t, the centripetal acceleration changes by a factor of (A) 1/2.(B) 4.(C) No change since the radius doesn't change.(D) 2.(E) 1/4.
Physics
1 answer:
Zigmanuir [339]4 years ago
4 0

Answer:

option B

Explanation:

given,

toy car is moving in circular track

speed is doubled— a change of a factor of 2

to find change in factor of acceleration

radius doesn't change

centripetal acceleration formula

           = \dfrac{v^2}{r}

velocity is change in factor of 2

so acceleration will be change at the factor of

           = \dfrac{(2v)^2}{r}

           = 2² = 4

so the correct answer is option B

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Help me find the acceleration
ANEK [815]

a = 3.09 m/s²

<h3>Explanation</h3>

This question doesn't tell anything about how long it took for the car to go through 105 meters. As a result, the <em>timeless </em>suvat equation is likely what you need for this question.

In the <em>timeless</em> suvat equation,

a = \dfrac{v^2 - u^2}{2\; x}

where

  • a is the acceleration of the car;
  • v is the <em>final</em> velocity of the car;
  • u is the <em>initial</em> velocity of the car; and
  • x is the displacement of the car.

Note that <em>v</em> and <em>u</em> are velocities. Make sure that you include their signs in the calculation.

In this question,

  • a is the unknown;
  • v = -10.9 \; \text{m} \cdot \text{s}^{-2};
  • u = -27.7 \; \text{m} \cdot \text{s}^{-2}; and
  • x = - 105 \; \text{m}.

Apply the <em>timeless</em> suvat equation:

a = \dfrac{v^{2} - u^{2}}{2\; x}\\\phantom{a} = \dfrac{(-10.9)^{2} - (-27.7)^{2}}{2 \times (-105)}\\\phantom{a} = 3.09 \; \text{m} \cdot \text{s}^{-2}.

The value of a is greater than zero, which is reasonable. Velocity of the car is negative, meaning that the car is moving backward. The car now moves to the back at a slower speed. Effectively it accelerates to the front. Its acceleration shall thus be positive.

7 0
3 years ago
Based on Newton’s 3rd law if you were to push on the wall with a force of 100 N, how much force would the wall push back towards
rusak2 [61]
The answer is 100N. Look up the definition of Newton's third law.
3 0
4 years ago
You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the
lana [24]

Answer:

<em>The fifth option is the correct answer: mv; 2 mv</em>

Explanation:

<u>Change of Momentum</u>

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

\Delta p=p_2-p_1

The momentum is computed as

p=mv

Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.

The clay has an initial speed v and a mass m, thus its initial momentum is

p_1=mv

When it hits the wall, it sticks, thus its final speed is 0 and

p_2=0

The change of momentum is

\Delta p=0-mv=-mv

The absolute change is mv

Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is

p_2=-mv

The change of momentum is

\Delta p=-mv-mv=-2mv

The absolute change is 2mv

The fifth option is the correct answer: mv; 2 mv

3 0
4 years ago
Please help. <br><br> Which describe colloids? Check all that apply.
rewona [7]

A) heterogeneous mixture & I believe B?


I know A is correct though


3 0
3 years ago
En un recipiente de cobre de forma rectangular de aproximadamente 3.5 m largo por 4.5m ancho tiene una temperatura en temporada
Darina [25.2K]

Answer:

A_f= 15,769 m²

Explanation:

Este es un ejercicio de dilatación térmica,  

          ΔA = (2α) A₀ ΔT

el arrea de recipiente

          A₀ = L A

          A₀ = 3,5 4,5

          A₀=  15,75 m²

el coeficiente de dilatación térmica es alfa = 16,6 10⁻⁶ C⁻¹

calculemos

            ΔA = 2 16,6 10⁻⁶  15,75 ( 40 -4)

            ΔA = 522,9 (36)  10⁻⁶  

            A= 1,88 10⁻²  m2

el cambio de volumen es

          ΔA = A_f – A₀

          A_f = A₀ +  ΔA

          A_f=  15,75 +1,88 10⁻²  

          A_f= 15,769 m²

3 0
3 years ago
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