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3 years ago

A body moves due north with velocity 40 m/s. A force is applied

Physics

1 answer:

marshall27 [118]3 years ago

4 0

Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

$\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v$

p: momentum

m: mass

$\Delta v$ : change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

$\Delta v=v_2-v_1$

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

$\Delta v =35m/s-40m/s=-5m/s$

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

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Two ac generators supply the same voltage. However, the first generator has a frequency of 1.2 kHz, and the second has a frequen

astra-53 [7]

Answer:

I_2 = 0.146 A

Explanation:

The formula for current in an inductor is;

I_rms = V_rms/X_L

Where X_L is inductance wirh formula 2πfL

So, I_rms = V_rms/X_L

Applying this to the two generators, we have;

First generator;

I_1 = V_rms/(2π(f_1)L)

And I_2 = V_rms/(2π(f_2)L)

Thus, to find the current in the second generator, we divide eq 1 by eq 2;

So,

I_2/I_1 = [V_rms/(2π(f_2)L)]/[V_rms/(2π(f_1)L)]

Some values will cance out leaving us with;

I_2/I_1 = f_1/f_2

I_2 = I_1(f_1/f_2)

Plugging in the relevant values ;

I_2 = 0.56(1.2/4.6)

I_2 = 0.146 A

6 0

4 years ago

Find the components to write this vector in unit vector notation: 63.5 A please help

IrinaVladis [17]

Vector is perpendicular to x axis or i component.

Hence i component is 0

j component is 63.5

$\\ \sf\longmapsto \overrightharpoon{A}=0\hat{i} +63.5\hat{j}$

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3 years ago

Car A is traveling at 20.0 m/s and car B at 27.0 m/s.

Savatey [412]

Take the moment car A starts to accelerate to be the origin. Then car A has position at time t

x = (20.0 m/s) t + 1/2 (2.10 m/s²) t²

and car B's position is given by

x = 300 m + (27.0 m/s) t

Car A overtakes car B at the moment their positions are equal:

(20.0 m/s) t + 1/2 (2.10 m/s²) t² = 300 m + (27.0 m/s) t

300 m + (7.00 m/s) t - (1.05 m/s²) t² = 0

==> t ≈ 20.6 s

4 0

3 years ago

1) Calculate the potential energy of a 5.00 kg object sitting on a 3.00 meter high ledge.

maria [59]

Answer:

15kg

Explanation:

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3 years ago

If 200 grams of water is to be heated from 24.0 degrees Celsius to 100.0 degrees Celsius to make a cup of tea, how much heat mus

Colt1911 [192]

Conveniently, some scientists have already figured out how much heat energy it takes to increase the temperature of one gram of water by exactly 1 degree Celsius. That is called the specific heat of water and it's value is 4.184J/g.

So simply multiply the specific heat with the number of grams and the number of degrees C like this:

$heat = 4.184J/g * 200g * 76^o C = 63,596.8J = 63.5968 kJ$

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4 years ago