I need help ASAP

Physics

1 answer:

ddd [48]2 years ago

3 0

I’m pretty sure the correct answer is plasma I am so so so so sorry if it’s incorrect

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A cable with mass 0.5 kilograms per meter (kg/m) is used to lift 150 kg of coal up a mine shaft 50 meters deep. Set up the integ

zalisa [80]

Answer:

$W=-\int_{0}^{50}[150-0.5y]dy$

Explanation:

the integral for the work is:

$W=\int\vec{F}\cdot d\vec{l}=\int(-M(y)g)dy$

the work is against the gravitational force. While the coal is going up, M(y) is changing due to the length of the cable is lower. We can describe this by using the following formula

$M(y)=150kg-0.5\frac{kg}{m}y$

Thus , the integral for the work is:

$W=-\int_{0}^{50}[150-0.5y]dy$

hope this helps!!

6 0

3 years ago

Some hydrogen gas is enclosed within a chamber being held at 200^\ { C} with a volume of 0.025 \rm m^3. The chamber is fitted wi

vlada-n [284]

Answer:

The final volume is $0.039 m^3$

Explanation:

Data:

Initial temperature: $T1=200C$

Final temperature: $T2=200C$

Initial pressure: $P1=1.50 \times10^6 Pa$

Final pressure: $P2=0.950 \times10^6 Pa$

Initial volume: $V1=0.025m^{3}$

Final volume: $V2=?$

Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:

$\frac{PV}{T}=nR$ (1)

With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$