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borishaifa [10]
3 years ago
7

Solve the system of equations by substitution. x+y=18 y=8x

Mathematics
2 answers:
stira [4]3 years ago
4 0

Answer:

2

Step-by-step explanation:

x + y = 18

y = 8x

x + 8x = 18

9x = 18

x = 18÷9

x = 2

Naddika [18.5K]3 years ago
3 0

Answer:

x=2, y=16

Step-by-step explanation:

x+y=18

y=8x

x+8x=18

x=2

y=16

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What’s is the domain of f(x) ?
marusya05 [52]

Answer:

Step-by-step explanation:

The inputs are -1, 0, 1 and 2.  This set represents the domain of the function.

4 0
3 years ago
It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0
3 years ago
Olsjsissjshsjsjsjsh help
stellarik [79]

Answer:

If u really struggle with maths u could use an application names photomath cuz it really helped me. Sry I can't help but I think photomath will be helpful

6 0
3 years ago
The sum of a rational number and an even integer is rational. A) Always True B) Sometimes True C) Usually True D) Never True
SOVA2 [1]
I think that the sum will always be a rational number
let's prove that


<span>any rational number can be represented as a/b where a and b are integers and b≠0

</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....

<span>so, 2 rational numbers can be represented as

</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)

their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd

1. the numerator and denominator will be integers
2. that the denominator does not equal 0

alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer

now the denominator
that is just a product of 2 integers so it is an integer


<span>2. we originally defined that b≠0 and d≠0 so we're good

</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
6 0
3 years ago
Last​ year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume
Arisa [49]

Answer:  The mean number of checks written per​ day  =0.3452

Standard deviation=0.5875

Variance  =0.3452

Step-by-step explanation:

Given : The total number of checks wrote by person in a year = 126

Assume that the year is not a leap year.

Then  1 year = 365 days

Let the random variable x represent the number of checks he wrote in one​ day.

Then , the mean number of checks wrote by person each days id=s given by :-

\lambda=\dfrac{126}{365}\approx0.3452

Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. \sigma^2=\lambda=0.3452

Standard deviation : \sigma=\sqrt{0.3452}=0.5875372328\approx0.5875

6 0
3 years ago
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