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2 years ago

I need help with this !!!!!

Mathematics

2 answers:

GenaCL600 [577]2 years ago

5 0

Answer:

-48

Step-by-step explanation:

-6(8)=-48

garri49 [273]2 years ago

5 0

Hey there!

When x = 8, the equation turns into -6 x 8

-6 x 8 = -48

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

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Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!

Ilya [14]

Answer:

$\boxed{\sf sin\ C =\frac{40}{41}}$

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}$

Substitute the respective values ,

$\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}$

<u>Hence the required answer is 40/41.</u>

6 0

3 years ago

please help ill give brain.liest your supposed to make inequality with the options it gives you in the picture their dragable

cupoosta [38]

Not sure(this might be wrong) but “30>p”

4 0

2 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$