At a carnival, Hayley gets to spin a prize wheel. It has a radius of 8 inches. What is the prize wheel's area?
2 answers:
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<span>First year is 30,000.
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.
An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53
S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes:
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227
<span>The individual yearly calculations are shown below: </span>
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.
An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53
S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes:
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227
<span>The individual yearly calculations are shown below: </span>
Given:
The bases of a trapezoid lie on the lines
To find:
The equation that contains the midsegment of the trapezoid.
Solution:
The slope intercept form of a line is
Where, m is slope and b is y-intercept.
On comparing with slope intercept form, we get
On comparing with slope intercept form, we get
The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.
The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.
So, the y-intercept of the required line is 1.
Putting m=2 and b=1 in slope intercept form, we get
Therefore, the equation of line that contains the midsegment of the trapezoid is .