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Mnenie [13.5K]
3 years ago
5

Find 3 consecutive numbers who sum is 216

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

the three consecutive numbers be 71, 72 and 73 respectively

Step-by-step explanation:

The computation of the 3 consecutive numbers is shown below:

Let us assume the three consecutive numbers be x , x+1 and x + 2

Now their sum is

x + x + 1 + x+ 2 = 216

3x + 3 = 216

3x = 216 -3

3 = 213

x = 71

x + 1 = 71 + 1 = 72

x + 2 = 71 + 2 = 73

Hence, the three consecutive numbers be 71, 72 and 73 respectively

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Step-by-step explanation:

To find the y-intercept, plug in x=0 in the original equation. (You want to find what y is when x=0)

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3y = -12 (2*0=0, so you can ignore that part)

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This narrows down our choices to either A or B.


To find the x-intercept, plug in y=0 into the original equation. (You want to find what x is when y=0)

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If our x intercept is -6 and our y intercept is -4, that makes our answer B.

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