Perimeter of a rectangle can be represented by 2* length + 2 * width
We can represent the width with the variable x
We can represent the length by the expression 3x-1
So, now we can make a forumla and solve
2(3x-1) + 2(x) = 30
6x-2+2x = 30
8x = 32
x = 4 is the width of the rectange.
Now we find the length
3(4)-1
11 = Length
Answer:
4m²-24mn+9n²
Step-by-step explanation:
- Separate equation out so it is (4m-3n)×(4m-3n)
- FOIL (First, Outside, Inside, Last) your polynomial
- Should have equation 4m²-12mn-12mn+9m²
- Combine like terms
- Result: 4m²-24mn+9m²
Answer:
50% offspring will be RR
Step-by-step explanation:
I set up my table and solved it I can teach you if you would like
Answer:
See below in bold.
Step-by-step explanation:
A). s(t)= -16t^2+64t+200
Converting to vertex form.
s(t) = -16 (t^2 - 4t) + 200
s(t) = -16 [(t - 2)^2 - 4] + 200
s(t) = -16(t - 2)^2 + 64 + 200
s(t) = -16(t - 2)^2 + 264
The maximum height is after 2 seconds and it is 264 feet.
B) The ball hits the ground when s(t) = 0 so we have:
-16t^2+64t+200 = 0
x [-64 +/- sqrt (64^2 - 4*-16*200) ] / -32
x = 6.06, -2.06
So the answer is 6.06 seconds.