Answer:
what do you want to do with this
Step-by-step explanation:
Answer:
a) 580 - 16n
b) 9850 - 271.72n
Step-by-step explanation:
a) starting number of bales = 580
each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day
After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is
original amount - amount lost = 580 - 16n
b)
First, we can calculate how much a bale weighs.
average = sum/count = 9850 kg / 580 ≈ 17 kg
Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be
starting - amount lost = 9850 - 271.72n
Answer:
=![\sqrt[3]{49x^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B49x%5E%7B2%7D%20%7D)
Step-by-step explanation:
We have been given the expression;
7 times x to the two thirds power which can be written mathematically as;
To express the above expression as a radical, we need to recall that;
![a^{\frac{b}{n}}=\sqrt[n]{a^{b}}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bb%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bb%7D%7D)
Therefore;
![(7x)^{\frac{2}{3}}=\sqrt[3]{(7x)^{2} }\\\\=\sqrt[3]{49x^{2} }](https://tex.z-dn.net/?f=%287x%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B%287x%29%5E%7B2%7D%20%7D%5C%5C%5C%5C%3D%5Csqrt%5B3%5D%7B49x%5E%7B2%7D%20%7D)
Answer:
Step-by-step explanation:
calculate the total
42+ 14 = 56
42/56 = x/100
4200 / 56x = 75
the answer is 75%
(5 1/4 in)(12 1/2 in)(4 in)
(21/4)(25/2)4=262.5 in^3
