First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
<span>3.3l : 900ml
= 3300 ml / 900 ml = 33/9 </span>
The 6th term of the geometric sequence is of -4096.
<h3>What is a geometric sequence?</h3>
A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.
The nth term of a geometric sequence is given by:
In which 
is the first term.
For this problem, we have that:
- The first term is
.
, hence the common ratio is q = -4.
Thus the 6th term of the sequence is found as follows:
More can be learned about geometric sequences at brainly.com/question/11847927
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Answer:
True
Step-by-step explanation:
It is true because the graph of 
passes through the point 
x = 16
y = 4
Substitute
4 = 16 - 12
4 = 4
Therefore, the answer is true.
