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Ivenika [448]
3 years ago
14

9.1% of 140 is what number

Mathematics
2 answers:
igomit [66]3 years ago
6 0
12.74 is the answer to the question
OlgaM077 [116]3 years ago
4 0
12.74 should be right
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6x — 5y = 15<br> x = y + 3<br> х =<br> y =
butalik [34]

<em>Replace all occurrences of x with y + 3 in each equation.</em>

<em>Replace all occurences of x in 6x - 5y = 15 with y + 3.</em>

<em>6 (y+3) -5y = 15</em>

<em>x = y + 3</em>

<em>Simplify 6 (y + 3) - 5y.</em>

<em>Simplify each term.</em>

<em>Apply the distributive property.</em>

<em>6y + 6 · 3 - 5y = 15</em>

<em>x = y + 3</em>

<em>Multiply 6 by 3.</em>

<em>6y + 18 - 5y = 15</em>

<em>x = y + 3</em>

<em>Subtract 5y from 6y.</em>

<em>y + 18 = 15</em>

<em>x = y + 3</em>

<em>Move all terms not containing y to the right side of the equation.</em>

<em>Subtract 18 from both sides of the equation.</em>

<em>y = 15 - 18</em>

<em>x = y + 3</em>

<em>Subtract 18 from 15.</em>

<em>y = -3</em>

<em>x = y + 3</em>

<em>Replace all occurences with y with -3 in each equation.</em>

<em>Replace all occurences of y in x = y + 3 with -3.</em>

<em>x = (-3) + 3</em>

<em>y = -3</em>

<em>Add -3 and 3.</em>

<em>x = 0</em>

<em>y = -3</em>

<em>The solution to the system is the complete set of ordered pairs that are valid solutions.</em>

<em>(0,-3)</em>

<em>The result can be shown in multiple forms. </em>

<em>Point Form:</em>

<em>(0,-3)</em>

<em>Equation Form:</em>

<em>x = 0, y = -3</em>

5 0
3 years ago
Read 2 more answers
The product of two mixed numbers that are each between 4 and 5 is between 16 and 25
nalin [4]
4.5x5=22.5

not sure if this is right, but hope it helps

6 0
4 years ago
List the following expressions in order from least to greatest value.
Sonja [21]
V57 v3 is Keats becuase it’s math and not why it’s not math it’s math just holy math with gif
8 0
3 years ago
Read 2 more answers
OK PLEASE HELP ME GUYS I ALWAYS HELP YOU so here it is
gtnhenbr [62]
F=P(1/2)^(t/h)
F=future amount
P=present amount
t=time elapsed
h=legnth of half life

P=96
t=2
h=1
F=96(1/2)^(2/1)
F=96(1/2)^2
F=96(1/4)
F=96/4
F=24 grams



grow by 35%
compound interest
F=P(1+rate)^time
F=95000(1+0.35)^10
F=95000(1.35)^10
F=95000(20.106555868618)
F=1910122.9075187  
8 0
3 years ago
10PTS: Prove/show that the limit of a constant as x approaches infinity is that constant?
Mashcka [7]
If the values of a function f(x) approach the value L as x approaches c, we say that f(x) has the limit L as x approaches c, and we write

In simpler terms, as x approaches c, the value of f(x) approaches L.
6 0
3 years ago
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