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sukhopar [10]
2 years ago
5

Can someone please help me with these two questions?

Mathematics
2 answers:
dimaraw [331]2 years ago
5 0

options d for the first and c for the second

SOVA2 [1]2 years ago
3 0

Answer:

D.9 1/3 and C.4

Step-by-step explanation:

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After Lois picks a value for b, Clark must solve the equation 2x + 7 - x = 4x + 2b – 3x - 3b.
puteri [66]

The value of b Lois gave to Clark to satisfy the given equation is -7.

The given parameters;

2x + 7 - x = 4x + 2b – 3x - 3b

To obtain the value of b, simplify the equation as follows;

2x + 7 - x = 4x + 2b – 3x - 3b

<em />

<em>collect similar terms together</em>

<em />

(2x - x) + 7 = (4x - 3x) + (2b - 3b)

x + 7 = x - b

(x - x) + 7 = -b

0 + 7 = -b

7 = -b

-7 = b

b = -7

Thus, the value of b Lois gave to Clark to satisfy the given equation is -7.

Learn more about simplification of algebraic expression here: brainly.com/question/8956927

5 0
2 years ago
A triangle with a base of 16 cm and a height of 9 cm.
bagirrra123 [75]

Answer: 288

Step-by-step explanation:

(16x9)x2

3 0
2 years ago
Can anyone help with this?
Iteru [2.4K]

Answer:

It can not be proved, so the last option

Step-by-step explanation:

Because there are no two angles in one triangle so it's not AAS or ASA. And there are no two sides so it's not SAS either.

5 0
2 years ago
Solve 3x+2y=7 and x-4y=-21 by using any method
kupik [55]

Answer:

(- 1, 5 )

Step-by-step explanation:

Using the method of substitution.

Given the 2 equations

3x + 2y = 7 → (1)

x - 4y = - 21 → (2)

Rearrange (2) expressing x in terms of y by adding 4y to both sides.

x = 4y - 21 → (3)

Substitute x = 4y - 21 into (1)

3(4y - 21) + 2y = 7 ← distribute and simplify left side

12y - 63 + 2y = 7

14y - 63 = 7 ( add 63 to both sides )

14y = 70 ( divide both sides by 14 )

y = 5

Substitute y = 5 into (3)

x = (4 × 5) - 21 = 20 - 21 = - 1

Solution is (- 1, 5 )

8 0
3 years ago
PLZ SOLVE PIC ATTACHED BELOW
ludmilkaskok [199]

Answer:

\tan(51°)  =  \frac{10}{x}  \\x =  \frac{10}{ \tan(51°) }  \\ x = \frac{10}{1.235}  \\ \boxed{ x = 8.1}

<h3>★ Value of x is <u>8.1</u>.</h3>

\sin(51°)=  \frac{10}{H}  \\ h =  \frac{10}{ \sin(51°) }  \\ H=  \frac{10}{0.777}  \\  \boxed{H= 12.8676}

<h3>★ Value of H is <u>12.8676</u>.</h3>

Remember:

  • tan∅=Perpendicular/Base
  • sin∅=Perpendicular/Hypotenuse

4 0
2 years ago
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