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Marrrta [24]
3 years ago
14

HELP i need to find area AND perimeter there is a triangle and a rectangle

Mathematics
2 answers:
arsen [322]3 years ago
7 0

Answer:

138 cm^2 = Area .          54 cm = Perimeter

Step-by-step explanation:

Find the area of the triangle-                                   <u>b * h</u> = A

                                                                                     2

                                                                                   <u>8 * 6</u> = A

                                                                                      2

                                                                                   48/2 = A

                                                                                     24 = A

Find the area of rectangle-                                        l * w = A

                                                                                   16 * 7 = A

                                                                                      112 = A

Add the areas together.                                            24 + 112 = 136 cm^2

Perimeter is adding up all the sides.                         s + s + s + s + s

                                                                                   16 + 7 + 8 + 10 + 13 = 54 cm

Komok [63]3 years ago
5 0

Answer:

<em>perimeter</em><em> </em><em>of </em><em>this </em><em>figure</em><em> </em><em>is </em><em>=</em><em> </em><em>5</em><em>4</em><em> </em><em>cm</em>

<em>and </em><em>area </em><em>of </em><em>traingle</em><em> </em><em>is </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em>*</em><em>base </em><em>*</em><em>height</em>

<em>so </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em>*</em><em>8</em><em>*</em><em>6</em>

<em>=</em><em>. </em><em>2</em><em>4</em><em>c</em><em>m</em><em>*</em><em>cm</em>

<em>and </em><em>area </em><em>of </em><em>rectangle</em><em> </em><em>=</em><em> </em><em>length</em><em> </em><em>*</em><em> </em><em>breadth</em><em> </em>

<em> </em><em>area </em><em>=</em><em> </em><em>1</em><em>1</em><em>2</em><em>c</em><em>m</em><em>*</em><em>cm</em>

<em>so </em><em>total </em><em>area </em><em> </em><em>=</em><em> </em><em>1</em><em>1</em><em>2</em><em>+</em><em> </em><em>2</em><em>4</em><em> </em><em>=</em><em> </em><em>1</em><em>3</em><em>6</em><em>c</em><em>m</em><em>*</em><em>cm </em>

hope it helps and your day will full of happiness

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Answer:

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Step-by-step explanation:

We don't have any numbers here to do calculations, so probably this is just an exercise in FACTORING. Also to practice that area is length times width.

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30 + 12x

can be factored several ways to be able to fill in the table.

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6 0
3 years ago
What is the relationship between area in the scale drawing and area on the on the actual tennis court if the scale is 1in.: 5ft.
sveticcg [70]

Given:

Length of the scale = 15.6 in.

Width of the scale = 7.2 in.

Scale of drawing = 1 in. : 5ft.

To find:

The ratio of area of the actual court to the area of the drawing (as a unit rate).

And to check whether it is the same as the ratio of length of the actual court to the length of the drawing.

Step-by-step explanation:

We have,

1 in. = 5ft.

Now, using this scale we get

15.6 in. = (15.6 × 5) ft =78 ft.

7.2 in. = (7.2 × 5) ft = 36 ft.

So, the actual length and width of tennis court are 78 ft and 36 ft respectively.

Area of actual tennis court is

Area=length\times width

Area=78\times 36

Area=2808\text{ ft}^2

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Area=15.6\times 7.2

Area=112.32\text{ in.}^2

Now, ratio of area of the actual court to the area of the drawing (as a unit rate) is

\dfrac{2808}{112.32}=\dfrac{25}{1}=25:1

Ratio of area is 25:1 and ratio of length is 5:1 both area not same.

Therefore, the ratio of area of the actual court to the area of the drawing (as a unit rate) is 25:1.

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Step-by-step explanation:

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B.29 + 1

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