Answer:
7
Step-by-step explanation:
3×7+1=22
2×7+8=22
Answer:
There is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43
Step-by-step explanation:
A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°F.
So, Null hypothesis:![H_0:\mu \geq 135](https://tex.z-dn.net/?f=H_0%3A%5Cmu%20%5Cgeq%20135)
Alternate hypothesis :![H_a:\mu](https://tex.z-dn.net/?f=H_a%3A%5Cmu%20%3C135)
To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133°F.
x=133
n = 32
Population Standard deviation =![\sigma = 3.3^{\circ}F](https://tex.z-dn.net/?f=%5Csigma%20%3D%203.3%5E%7B%5Ccirc%7DF)
Formula :![z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}\\\\z=-3.428](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B133-135%7D%7B%5Cfrac%7B3.3%7D%7B%5Csqrt%7B32%7D%7D%7D%5C%5C%5C%5Cz%3D-3.428)
z=-3.43
Refer the z table for p value
p value = 0.0003
![\alpha = 0.10](https://tex.z-dn.net/?f=%5Calpha%20%3D%200.10)
p value < α
So, we failed to accept null hypothesis
Hence there is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43
Answer:
4th grade questions?
I can easily help you with those.
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