Given:
Polynomial is
.
To find:
The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.
Solution:
The sum of given polynomial and the square of the binomial (x-8) is

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)

On combining like terms, we get


Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is
.
Answer:
first one is 32
the second one is 53
Step-by-step explanation:
Answer:
Step-by-step explanation:
The general equation of a circle is , x² + y² + 2gx + 2fy + c = 0
Substituting the three points we get the following equations,
2g +14f +c=-50
14g - 2f + c =-50
16g +12f + c = -100
Solving these equations we get,
g =-4, f = -3, c = 0
Hence general equation of circle is,
x² + y² - 8x - 6y = 0