The shape of the cross-section is a rectangle and the area of the cross section is
square units.
<h3>
Analysis of a cube</h3>
Let be a cube whose <em>side</em> length is
and lines
and
intersects the cube, then we have a <em>cross</em> section formed by points A, C, E, H. Since
,
,
and
, then
by 45-90-45 right triangle.
In addition, we know that
,
and
. Hence, we conclude that the cross-section is a rectangle. Hence, the area of the <em>cross-section</em> area is:
(2)
If we know that
, then the area of the cross-section is:
![A = \sqrt{2}\cdot 4^{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Csqrt%7B2%7D%5Ccdot%204%5E%7B2%7D)
![A = 16\sqrt{2}](https://tex.z-dn.net/?f=A%20%3D%2016%5Csqrt%7B2%7D)
The shape of the cross-section is a rectangle and the area of the cross section is
square units.
To learn more on quadrilaterals, we kindly invite to check this verified question: brainly.com/question/25240753
![x/3 + 3 = -5-x](https://tex.z-dn.net/?f=%20x%2F3%20%2B%203%20%3D%20-5-x%20)
Subtract 3 on both sides.
![x/3 = -5-x](https://tex.z-dn.net/?f=%20x%2F3%20%3D%20-5-x%20)
Add x....
![4x/3 = -5](https://tex.z-dn.net/?f=%204x%2F3%20%3D%20-5%20)
<h2>BONUS!!</h2>
Multiply by 3
![4x = -15](https://tex.z-dn.net/?f=%204x%20%3D%20-15%20)
Divide by 4
Answer:
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Answer:
Explanation:
Given that y varies inversely as x, we have:
![\begin{gathered} y\propto\frac{1}{x} \\ \\ \Rightarrow y=\frac{k}{x} \\ \\ OR \\ yx=k \\ \text{where k is the constant of proportionality} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%5Cpropto%5Cfrac%7B1%7D%7Bx%7D%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20y%3D%5Cfrac%7Bk%7D%7Bx%7D%20%5C%5C%20%20%5C%5C%20OR%20%5C%5C%20yx%3Dk%20%5C%5C%20%5Ctext%7Bwhere%20k%20is%20the%20constant%20of%20proportionality%7D%20%5Cend%7Bgathered%7D)
SInce x = 7 whe y = 5, we can find k
k = 7*5 = 35
so
yx = 35
To find y