$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=3(x-3) \\\\\\ y-1=3x-9\implies y=3x-8$

7 0

3 years ago

Suppose given an isosceles triangle with a leg measuring 5 in. Two lines are drawn through some point on the base, each parallel

enot [183]

We have an isosceles triangle and 2 lines that are drawn through some ( any ) point on the base. The both lines are parallel to one of the legs. Then those lines with the legs of the triangle make a parallelogram. We can say that x and y are the sides of the parallelogram. Then: x + y = 5 in. And the perimeter of the parallelogram: P = 2 x + 2 y = 2 * ( x + y ).
P = 2 * 5 = 10 in. The rest is in the attachment.
Answer: The perimeter of the constructed parallelogram is 10 inches.

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3 years ago