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2 years ago

The radius of the large sphere is double the radius of the

Mathematics

1 answer:

kozerog [31]2 years ago

8 0

Answer:

Given:

Radius of large sphere: R1

Volume of sphere: V1

Radius of small sphere: R2

Volume of sphere: V2

R1=2R2

We know that:

Volume of a sphere: 4/3πR^3

Volume of large sphere: 4/3πR1^3

Now we know that R1=2R2(given)

Thus volume of large sphere(V1) 32/3πR2^3.

Volume of small sphere(V2): 4/3πR2^3.

Ratio of volume of large sphere to small sphere is 8:1.

Step-by-step explanation:

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The product of 8 and the sum of a number x and 3

Olin [163]

Answer:

8(x+3)

Step-by-step explanation:

thats the answer

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3 years ago

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Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems

Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for $(x_{1},y_{1}) and (x_{2},y_{2})$

Use the distance formula to find the length = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length = $\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\$

length = $\sqrt{80}$

length = 8.94

Use the distance formula to find the width = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width = $\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\$

width = $\sqrt{(-10 )^{2} + (11 )^{2}}\\$

width = $\sqrt{100 + 121}\\$

width = $\sqrt{221}$

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

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2 years ago

Write the equation of the line that passes through the points (5, -9) and (5,8). Put your answer in fully reduced point-slope fo

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Answer:

x=5 is what i got from a calculaotr

Step-by-step explanation:

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