Answer:
Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg Capillary colloid osmotic pressure (OPc) = 25 mmHg Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg. The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
Explanation:
Capillary hydrostatic pressure (HPc) = 30 mmHg
Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg
Capillary colloid osmotic pressure (OPc) = 25 mmHg
Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient
Hydrostatic pressure gradient = Capillary hydrostatic pressure - Interstitial hydrostatic pressure = 30mmHg - 0 mmHg = 30 mmHg
Oncotic pressure gradient = Capillary colloid osmotic pressure - Interstitial fluid colloid osmotic pressure =25 - 2 = 23 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient = 30 mmHg - 23 mmHg = 7 mmHg.
Hence, The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
The answer is C. This is because nucleotide elongation involves the addition of a nucleotide to the 3 prime carbon of the previous nucleotide carbon ring. This involves a dehydration reaction between the phosphate group on the 5 prime carbon of the last nucleotide to the hydroxyl group of the 3 prime carbon of the previous nucleotide.
The answer for this is Density
