A gas occupies 12.3 liters at a temperature of 40 K. What is the volume when the temperture is increased to 60 K?
1 answer:
Answer:
The answer to your question is V2 = 18.45 l
Explanation:
Data
Volume 1 = V1 = 12.3 l
Temperature 1 = T1 = 40°K
Volume 2 = V2 = ?
Temperature 2 = T2 = 60°K
Process
To solve this problem use Charles' law
V1/T1 = V2/T2
-Solve for V2
V2 = V1T2 / T1
-Substitution
V2 = (12.3 x 60) / 40
-Simplification
V2 = 738 / 40
-Result
V2 = 18.45 l
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