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Alex Ar [27]
3 years ago
5

A gas occupies 12.3 liters at a temperature of 40 K. What is the volume when the temperture is increased to 60 K?

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

The answer to your question is  V2 = 18.45 l

Explanation:

Data

Volume 1 = V1 = 12.3 l

Temperature 1 = T1 = 40°K

Volume 2 = V2 = ?

Temperature 2 = T2 = 60°K

Process

To solve this problem use Charles' law

              V1/T1 = V2/T2

-Solve for V2

              V2 = V1T2 / T1

-Substitution

              V2 = (12.3 x 60) / 40

-Simplification

              V2 = 738 / 40

-Result

               V2 = 18.45 l

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what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?
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A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (M1V1 = M2V2).

Utilize the titration method of M1V1 = M2V2 in view that we're given the concentrations of every compound and the quantity of KOH. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

  • M1 = initial mass
  • V1= initial volume
  • M2 = final mass
  • V2= final volume
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