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maria [59]
4 years ago
9

One of the largest cypress trees in Florida has a tree trunk with a diameter of about 3.5 meters. What is the source of most of

the carbon in the cypress tree’s trunk?
The carbon created by the tree during photosynthesis.
The carbon stored in tree seeds.
The carbon dioxide molecules the tree absorbed from the atmosphere.
The nutrients containing carbon that the tree absorbed from the soil.
Chemistry
1 answer:
jeyben [28]4 years ago
8 0

I pretty sure it is the last one. Not completely sure though, hope this helps

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A chemistry student needs 10.0g of ethanolamine for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the
iogann1982 [59]

Answer: The volume of ethanolamine the student should pour out is 9.80cm^3

Explanation:

To calculate the volume of ethanolamine we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of ethanolamine = 1.02g/cm^3

Mass of ethanolamine = 10.0 g

Volume of ethanolamine = ?

Putting values in above equation, we get:

1.02g/cm^3=\frac{10.0g}{\text{Volume of ethanolamine}}\\\\{\text{Volume of ethanolamine}=\frac{10.0g}{1.02g/cm^3}=9.80cm^3

Thus the volume of ethanolamine the student should pour out is 9.80cm^3

4 0
4 years ago
Drag each label to the correct location on the image identify the parts of the energy diagram
diamong [38]
If you would’ve attached a picture I’m sure it would’ve been a lot easier.
4 0
3 years ago
Read 2 more answers
Why do all atoms of an element have the same atomic number, although they may have
Evgesh-ka [11]

Answer:

Here’s what I get.

Explanation:

  • The atomic number is the number of protons in the nucleus of an atom.
  • The number of protons determines the number of electrons.
  • The number of electrons determines the chemical properties of the element,

Thus, the atomic number determines the identity of the element.

The atomic mass does not affect the chemical properties, so different isotopes of an element behave alike.

5 0
4 years ago
In the following reaction, Zn is Zn(s) H2SO4(aq) --> ZnSO4(aq) H2(g) A.Reduced B.Oxidized C.This is not a redox reaction D.An
Svetlanka [38]

<u>Answer:</u> The correct option is B) oxidized

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

For the given chemical reaction:

Zn+H_2SO_4+S\rightarrow ZnSO_4+H_2

<u>On the reactant side:</u>

Oxidation number of H = +1

Oxidation number of Zn = 0

Oxidation number of S = +6

Oxidation number of O = -2

<u>On the product side:</u>

Oxidation number of H = 0

Oxidation number of Zn = +2

Oxidation number of S = +6

Oxidation number of O = -2

As the oxidation number of Zn is increasing from 0 to +2. Thus, it is getting oxidized. Similarly, the oxidation number of H is decreasing from +1 to 0. Thus, it is getting reduced.

Hence, the correct option is B) oxidized

4 0
3 years ago
Calculate the force of gravity on a 1-Kilogram box located a point 1.3x10^7 meters from the center of Earth if the force on a 2.
k0ka [10]

The force of gravity on the 1 kg box is 2 N.

The formula for the force of gravity <em>F</em> on an object with mass <em>m</em> is

<em>F</em> = (<em>GmM</em>)/<em>d</em>²

Since <em>G</em>, <em>M</em> , and <em>d</em> are the same for both objects, (<em>GM</em>)/<em>d</em>² = a constant = <em>k </em>). Then, we can write

<em>F = km </em>

<em>F</em>₂/<em>F</em>₁ = <em>m</em>₂/<em>m</em>₁

<em>F</em>₂ = <em>F</em>₁ × <em>m</em>₂/<em>m</em>₁

If the 2.5 kg box is object 1,

<em>F</em>₂= 6.1 N × (1 kg/2.5 kg) = 2 N

<em>Note</em>: The answer can have <em>only one significant figure</em> because that is all you gave for the mass of the 1 kg object.

6 0
3 years ago
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