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2 years ago

Help me please I need to turn this in at 10:50 PM

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

Answer:

volume

Step-by-step explanation:

because cubed represents volume, and squared represents area

Hope this helps with your deadline :)

If you need further explanation, feel free to ask!

- profparis

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What is equidistant from the vertices of a triangle.

docker41 [41]

Answer:

The circumcenter of a triangle is a point that is equidistant from all three vertices.

Step-by-step explanation:

What is equidistant from the vertices of a triangle?

The circumcenter of a triangle is a point that is equidistant from all three vertices.

5 0

2 years ago

Can some one help me with this question

alisha [4.7K]

Answer:

1/7

Step-by-step explanation:

you divide both numbers by 4

7 0

3 years ago

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Pls help!!!!!!!!!!!!!!!

Tresset [83]

Answer: The radius would be twelve

Step-by-step explanation:

The radius of a sphere would be 12 cm. By putting the value of volume we can find the radius of the sphere. The radius of a sphere would be 12 cm.

8 0

3 years ago

A circle with radius of 5 cm sits inside a 11 cm * 11 cm rectangle.

Nadusha1986 [10]

Answer:

42.43 $cm^{2}$

Step-by-step explanation:

Given:

A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.

Question asked:

What is the area of the shaded region as shown in the figure ?

Solution:

First of all calculate area of circle and then area of rectangle:-

$Area\ of\ cirle=\pi r^{2}$

$=\frac{22}{7} \times5\times5\\ \\ =\frac{550}{7}\\ \\=78.571\ cm^{2}\\$

<u>As here length an width both are 11 cm, we can say that this is a square.</u>

<u /> $Area\ of\ square=(Side)^{2}$

$=11\times11=121\ cm^{2}$

Now, area of shaded region = Area of square - Area of circle

= 121 - 78.571 = 42.429 $cm^{2}$

Therefore, the area of the shaded region will be 42.43 $cm^{2}$

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5 0

3 years ago

arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)

cupoosta [38]

We have to rationalize the denominator:
$\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\ \frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{ \sqrt{x+y-2}+ \sqrt{x+y+2} }= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-(x+y+2)}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-x-y-2}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2} }{-4}= \\ \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{2}$

6 0

3 years ago

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