Answer:
In styrene, there is a phenyl group which is electron-withdrawing. So the electronic density in the double bonds increases, hence easy to associate as monomers. While in methoxystyrene, there is a carbonyl group which is not electron deficient. so no easy association with monomers.
Explanation:
![{ \sf{styrene \: is \: phenylethene \: }} \\ { \sf{its \: polymer \: is \: polystyrene}}](https://tex.z-dn.net/?f=%7B%20%5Csf%7Bstyrene%20%5C%3A%20is%20%5C%3A%20phenylethene%20%5C%3A%20%7D%7D%20%5C%5C%20%7B%20%5Csf%7Bits%20%5C%3A%20polymer%20%5C%3A%20is%20%5C%3A%20polystyrene%7D%7D)
Answer:
The H+ (aq) concentration of the resulting solution is 4.1 mol/dm³
(Option C)
Explanation:
Given;
concentration of HA,
= 6.0mol/dm³
volume of HA,
= 25.0cm³, = 0.025dm³
Concentration of HB,
= 3.0mol/dm³
volume of HB,
= 45.0cm³ = 0.045dm³
To determine the H+ (aq) concentration in mol/dm³ in the resulting solution, we apply concentration formula;
![C_iVi = C_fV_f](https://tex.z-dn.net/?f=C_iVi%20%3D%20C_fV_f)
where;
is initial concentration
is initial volume
is final concentration of the solution
is final volume of the solution
![C_iV_i = C_fV_f\\\\Based \ on \ this\ question, we \ can \ apply\ the \ formula\ as;\\\\C_A_iV_A_i + C_B_iV_B_i = C_fV_f\\\\C_A_iV_A_i + C_B_iV_B_i = C_f(V_A_i\ +V_B_i)\\\\6*0.025 \ + 3*0.045 = C_f(0.025 + 0.045)\\\\0.285 = C_f(0.07)\\\\C_f = \frac{0.285}{0.07} = 4.07 = 4.1 \ mol/dm^3](https://tex.z-dn.net/?f=C_iV_i%20%3D%20C_fV_f%5C%5C%5C%5CBased%20%5C%20on%20%5C%20this%5C%20question%2C%20we%20%5C%20can%20%5C%20apply%5C%20the%20%5C%20formula%5C%20as%3B%5C%5C%5C%5CC_A_iV_A_i%20%2B%20C_B_iV_B_i%20%3D%20C_fV_f%5C%5C%5C%5CC_A_iV_A_i%20%2B%20C_B_iV_B_i%20%3D%20C_f%28V_A_i%5C%20%2BV_B_i%29%5C%5C%5C%5C6%2A0.025%20%5C%20%2B%203%2A0.045%20%3D%20C_f%280.025%20%2B%200.045%29%5C%5C%5C%5C0.285%20%3D%20C_f%280.07%29%5C%5C%5C%5CC_f%20%3D%20%5Cfrac%7B0.285%7D%7B0.07%7D%20%3D%204.07%20%3D%204.1%20%5C%20mol%2Fdm%5E3)
Therefore, the H+ (aq) concentration of the resulting solution is 4.1 mol/dm³
Answer:
The meaning and usefulness of the mole Page 2 2 • One mole of NaCl contains 6.022 x 1023 NaCl formula units. Use the mole quantity to count formulas by weighing them. The mass of an atom in amu is numerically the same as the mass of one mole of atoms of the element in grams.
Explanation:
Answer:
The amount of glue used, the material and how much of it you're using every time you test each glue, the temperature of the room, etc.
Explanation:
There are many answers to this question but think about the obvious ones first. Obviously you'll need to use the same amount of glue every time you're testing each type. The material used is also important and how much of the material you're using because different types of glue can work better with different materials, as well as how much material you're using. The temperature of the room can affect how well each glue holds up because often glue dries easier/quicker with heat, so in your experiment to make it fair you need to make sure that each glue is tested in the same environment.
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