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LUCKY_DIMON [66]
3 years ago
12

Why does the density of a substance stay constant even if the mass of the substance increases?

Chemistry
1 answer:
olganol [36]3 years ago
5 0

Answer:

If the mass stays constant the object's density decreases as the volume increases. ... Because the property of density is a constant for all variables, density can be used to identify the material an object is made of.

Explanation:

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PLLLLLLLZ HELP IS NEEDED ASAP I WOULD REALLY APPRECIATE IT
Lesechka [4]

Answer:

1)Reactants

2)Light

3)An item that can increase reaction rates

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Less molecules lower the chance for collisions

The more collisions there are the higher the reaction rate

5 0
3 years ago
Balance the following equation. Then, given the moles of reactant or product below, determine the corresponding amount in moles
Mrrafil [7]

Answer:

Option a → 4 mol NH₃

Explanation:

This the unbalanced reaction

NH₃  +  O₂  ⟶  N₂  +  H₂O

The balanced reaction:

4NH₃  +  3O₂  →  2N₂  +  6H₂O

4 mol of ammonia

3 mol of oxygen

2 mol of nitrogen

6 mol of water

6 0
3 years ago
Calculate the energy provided by a slice of bread containing 2 g of protein, 1 g of fat, and 20 g of carbohydrate. record your a
vichka [17]
 the energy gained by proteins and carbohydrates differs from the energy gained by fats.
proteins and carbohydrates both give 4 kcal per gram 
fats give 9 kcal per gram
mass of proteins - 2 g
energy given by proteins - 2 g x 4 kcal/g = 8 cal
mass of carbohydrates - 20 g 
energy given by carbohydrates - 20 g x 4 kcal/g = 80 cal
mass of fat - 1 g 
energy given by fat - 1 g x 9 kcal/g = 9 cal
total energy = 8 + 80 + 9 = 97 kcal
energy = 97 kcal
8 0
3 years ago
Is sugar a compound?
kvv77 [185]
Sugar is a compound. 
 <span>C12H22O<span>11</span></span>
3 0
3 years ago
Can someone help me please? I’d appreciate it! Also please do not send me a link or delete your answer! Thanks
chubhunter [2.5K]

Answer:

14.53ML

Explanation:

V1=218

V2=?

P2=15p1

USING BOYLE'S LAW

P1V1=P2V2

V2=P1V1/P2=P1(218ML)/15P1

=14.53ML

5 0
3 years ago
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