Answer:
— The molality of chloride ions in 300g of water is. A) 1.00 molal. B) 0.500 molal. C) 0.0553 molal. D) 0.111 molal.
First, determine the number of moles of gold.
Number of moles = 
Given mass of gold =
Molar mass of gold = 196.97 g/mol
Put the values,
Number of moles of gold = 
= 
or 
Now, molarity = 
Put the values, volume of ocean =
Molarity = 
= 
Thus, average molar concentration =
Answer:
The projection of the Fisher projection of D-Fructose and D-glucose is that The carbonyl carbon in D-glucose is carbon 1 (aldehyde), whereas in D-fructose, the carbonyl group is on carbon 2 (ketone).
Explanation:
An aldehyde is a compound containing a functional group with the structure −CHO, consisting of a carbonyl center and
A ketone is a functional group with the structure RC(=O)R', where R and R' can be a variety of carbon-containing substituents.
Answer:
Mass = 427.05 g
Explanation:
Given data:
Formula units of sodium chloride = 4.38 ×10²⁴
Mass of NaCl = ?
Solution:
One mole contain formula units = 6.022 ×10²³
4.38×10²⁴ formula units × 1mol /6.022 ×10²³ formula units
0.73 ×10¹ mol
7.3 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 7.3 mol × 58.5 g/mol
Mass = 427.05 g
