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Hoochie [10]
2 years ago
14

The volume of a gas is halved and the temperature is unchanged. The pressure of the gas is

Chemistry
2 answers:
ololo11 [35]2 years ago
4 0

this is base don Boyle law

PV= constant at constant temperature

P1V1=P2V2

here the V2= V1/2

P1 *V1 =P2* V1/2

P1 *2 = P2

it mean pressure of gas is doubled




AysviL [449]2 years ago
4 0

Answer:

The pressure will get doubled.

Explanation:

On the basis of the ideal gas equation, the pressure relies upon the gas constant, the number of moles, the volume of the gas, and the temperature. In the given case, the temperature is constant, and let us assume that the number of moles is also constant for a specific gas. Thus, the pressure only modifies with the change in volume. According to the equation, PV = nRT or P = nRT / V, the pressure is inversely proportional to the volume, thus, if the volume is reduced, the pressure will also get increase.

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80.0 mL of 0.30 M NaOH and 80.0 mL of 0.30 M HCl are mixed together. What is the approximate pH
Licemer1 [7]

Answer:

  • <u><em>Neutral</em></u>

Explanation:

The number of moles of solute is equal to product of the molar concentration (molarity) and the volume (in liters) of solution.

Since the volumes and the molar concentrations of the<em> NaOH </em>and <em>HCl </em>solutions mixed are equal, each one of them contributes the same number of moles of solute.

Since every mol of NaOH produces one mol of OH⁻ ions and every mol of HCl produces one mol of H⁺ ion, the number of moles of OH ⁻ and H⁺ in solution are equal.

Thus, OH⁻ and H⁺ ions will be neutralized by the reaction:

  • OH⁻ (aq) + H⁺ (aq) ⇄ H₂O (l)

Which is strongly shifted to the right and has <em>neutral pH</em>.

Hence, you conclude that the approximate <em>pH of the solution is neutral.</em>

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3 years ago
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7 0
3 years ago
What is the ph of a buffer prepared by adding 0.809 mol of the weak acid ha to 0.608 mol of naa in 2.00 l of solution? The disso
Anarel [89]

The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247

The pH of the buffer can be known as

pH = pK_{a} + log[\frac{[A-]}{[HA]}}]

The concentration of [A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\

Similarly, the concentration of [HA] = \frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404

Then the pH of the buffer will be

pH = 6.247 + log [ 0.304/0.404]

pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236

So, the pH of the buffer is 6.1236.

5 0
3 years ago
What is the concentration of hydronium ion in a 0.121 M HCl solution?
kogti [31]

Answer:

C) 0.121 M

Explanation:

HCl + H₂O = H₃O⁺ + OH⁻

.121M              .121M

HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .

So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.

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