If the width is 9x², then the length is 27x^5+9x^4-18x^3/9x², which equals 3x³+x²+2x. ☺☺☺☺
The answer for the equation is 21/5 or 4.2.
The launchers height above the ground at zero distance h(x)+0+0+.4= 4 meaning that the height is 4 <span />
A calculator (addition) has one and exactly 1 output for every addition problem that you use as an imput
Step One
Find the Volume in ccs.
V= l*w*h
l =40 mm
w = 25 mm
h = 2 mm
V = 40*35 * 2
V = 2800 mm^3
Step Two
Find the weight
1 mm^3 = 0.0005
2800 mm^3 = x <<<<< answer 1
Cross multiply.
1x = 2800 * 0.0005
x = 1.4 ounces. <<<<< answer 2