A particle is moving along the number line so that its distance (in meters) from the origin at any time t (in seconds) is given by s(t) = 8t2 + ln t. The velocity of the particle at t = 1 second is:
1 answer:
Answer:
The velocity is 17 m/s
Step-by-step explanation:
To find the velocity, we find the first differential of the displacement
That will be
S’(t) = 16t + 1/t
We simply proceed to replace t with 1
That will give;
16(1) + 1/1
= 16 + 1 = 17 m/s
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