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2 years ago

By how much is the product of 27 and 13 greater than their sum?

2 answers:

8 0

Well its quite simple...
the product of 27 and 13 is 351 (which is found by multiplying 27 and 13)
and the sum of 27 and 13 is 40 (which is found by adding 27 and 13 together)

therefore to work out the difference you have to do:
351 - 40 which equals 311

so 311 is your answer

zepelin [54]2 years ago

4 0

Product : - 27 * 13 = 351
Sum = 27 + 13 = 40

Thus, difference = 351 - 40 = 311

Thus, the product of 27 and 13 is 311 numbers greater than the product.

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we have

$3x^{2} -8x+5$

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$3x^{2} -8x+5=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$3x^{2} -8x=-5$

Factor the leading coefficient

$3(x^{2} -(8x/3))=-5$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$3(x^{2} -(8x/3)+(16/9))=-5+(16/3)$

$3(x^{2} -(8x/3)+(16/9))=(1/3)$

Rewrite as perfect squares

$3(x-(4x/3))^{2}=(1/3)$

$(x-(4x/3))^{2}=(1/9)$

square roots both sides

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$x=\frac{4}{3}(+/-) \frac{1}{3}$

the roots are

$x=\frac{4}{3}+ \frac{1}{3}=\frac{5}{3}$

$x=\frac{4}{3}- \frac{1}{3}=\frac{3}{3}=1$

$3x^{2} -8x+5=3(x-\frac{5}{3})(x-1)=(3x-5)(x-1)$

therefore

<u>the answer is the option</u>

$(3x-5)(x-1)$

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3 years ago

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Answer:

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Since we are trying to find the probability for a sequence of events then we need to multiply the probability of each event happening separately from each other. Since the probability of it raining on a single day is 2/3 we need to multiply this value with itself 4 times (one for each day).

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Answer:

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