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Norma-Jean [14]
2 years ago
13

Enter the solutions from least to greatest. (3x -6)(-x +3)=0

Mathematics
1 answer:
DiKsa [7]2 years ago
5 0

Answer:

x = 2, 3.

Step-by-step explanation:

<u>Since the equation equals 0, we can determine that:</u>

3x-6=0

-x+3=0

Let's solve 3x-6=0.

<u>Add 6 to both sides of the equation:</u>

3x=6

<u>Divide both sides by 3:</u>

x=2

Let's solve -x+3=0.

<u>Subtract 3 from both sides of the equation:</u>

-x=-3

<u>Divide by -1:</u>

x=3

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Answer:

(3,2)

Step-by-step explanation:

take negative from inside bracket as x and contant outside as y, and done

6 0
3 years ago
A box contains 5 red marbles, 6 white marbles, and 8 blue. If a Marble is randomly selected from the box, what is the likely hoo
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Likelihood of white: 6/19
6 0
2 years ago
Graph f(x)=−3/4x−4 . Use the line tool and select two points to graph the line.
lions [1.4K]

Answer:

Two points on the line would be (0, -4) and (4, -7)

Step-by-step explanation:

In order to find this, we can start at the y-intercept. The y-intercept is the constant at the end of the equation. In this case it is -4, which gives us the first point of (0, -4).

We can find the second point by using the numerator of the slope to determine how much we go up or down (-3) and the denominator for how much we go left to right (4). So we add the 4 to the x value and add the -3 to the y value.

(4, -7)

3 0
3 years ago
Which value is NOT a solution of 8x3 – 1 = 0?
Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Step-by-step explanation:

Considering the equation

8x^3\:-\:1\:=\:0

Steps to solve the equation

8x^3-1=0

\mathrm{Add\:}1\mathrm{\:to\:both\:sides}

8x^3-1+1=0+1

\mathrm{Simplify}

x^3=\frac{1}{8}

\mathrm{Divide\:both\:sides\:by\:}8

\frac{8x^3}{8}=\frac{1}{8}

\mathrm{Simplify}

x^3=\frac{1}{8}

As

\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}

So,

x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}

Therefore,

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Keywords: solution, value

Learn more about equation solution from  brainly.com/question/1679491

#learnwithBrainly

7 0
3 years ago
Can you help me with this question please? I will reward 20 points for best answer.
swat32

Answer:

Demand: q = -50p + 1200

Supply: q = 40p

Step-by-step explanation:

First let's define our variables.

q = quantity of T-shirts

p = price

We know that when p = 12, q = 600.  When p increases by 1, q decreases by 50.  So this is a line with slope -50 that passes through the point (12, 600).  Using point-slope form to write the equation:

q - 600 = -50 (p - 12)

Converting to slope-intercept form:

q - 600 = -50p + 600

q = -50p + 1200

Similarly, we know that when p = 9.75, q = 600 - 210 = 390.  When p increases by 1, q increases by 40.  So this is a line with slope 40 that passes through the point (9.75, 390).  Using point-slope form to write the equation:

q - 390 = 40 (p - 9.75)

Converting to slope-intercept form:

q - 390 = 40p - 390

q = 40p

5 0
2 years ago
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