Can someone please help me with this problem:(
1 answer:
You might be interested in
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude
Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
Learn more about vectors;
#SPJ1
Answer:
Width of the rectangle = 6.7 ft
length of the rectangle = 10.7 ft
Step-by-step explanation:
ABCD is the rectangle.
AB = length of the rectangle = 4 + x ft
BC = width of the rectangle = x ft
AC = Diagonal of the rectangular field = 12 ft
Since ΔABC is the Right angle triangle. So
By solving above equation we get
x = 6.7 ft
Thus is the width of the rectangle.
And length of the rectangle = 4 + x
⇒ 4 + 6.7
⇒ 10.7 ft
