2.5 x 10^24 molecules of C4H10
Answer:
The biological sample that pregnancy tests use to detect pregnancy is urine
We can use the heat
equation,
<span>Q = mcΔT
</span>
Where Q is the amount
of energy transferred (J), m is the mass of the substance (kg), c is the
specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
In this problem there is no any data about initial temperature of the water. So, we can assume that given temperature of 5.2 °C as the temperature difference.
Q = 348 J
m = ?
c = 4.186 J g⁻¹ °C⁻¹
ΔT = 5.2 °C<span>
By applying the formula,
348 J = m x </span>4.186 J g⁻¹ °C⁻¹ x 5.2 °C<span>
m = 15.99 g
Hence, the grams of water is 15.99.</span>
Since that E°cell =E°cathode - E°anode then
0.62V = 0.34 - E°anode
Therefore E° anode is = -0.28V
