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3 years ago

HELPPPPPPPP I NEEED TO PASS

Chemistry

2 answers:

Monica [59]3 years ago

7 0

I believe it might be c I might wrong

worty [1.4K]3 years ago

4 0

Answer:

your answer my friend is C

-for sure its C

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What is an element? Arrow

Butoxors [25]

Answer:

One arrow is positioned in each box according to Hund's Rule which tells us to maximise the number of unpaired electrons in orbitals of the same subshell, and, to give those electrons the same "spin" (parallel spin).

Explanation:

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2 years ago

Electrons are attracted to ________________. protons other electrons neutrons all the particles

rjkz [21]

Protons .because electron has negative charge and proton has positive charge.

6 0

3 years ago

sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction

prisoha [69]

Answer:

2.76 × 10⁻¹¹

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹: 0 0 -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

$\text{The relationship between $\Delta G^{\circ}$ and K is}\\\Delta G^{\circ} = -RT \ln K$

T = (25.0 + 273.15) K = 298.15 K

$\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}$

3 0

3 years ago

An aqueous solution of calcium hydroxide is standardized by titration with a 0.112 M solution of hydrobromic acid. If 15.2 mL of

TiliK225 [7]

Answer:

0.0457 M

Explanation:

The reaction that takes place is:

2HBr + Ca(OH)₂ → CaBr₂ + 2H₂O

First we calculate how many moles of acid reacted, using the HBr solution's concentration and volume:

Molarity = Moles / Volume

Molarity * Volume = Moles

0.112 M * 12.4 mL = 1.389 mmol HBr

Now we convert HBr moles to Ca(OH)₂ moles, using the stoichiometric ratio:

1.389 mmol HBr * $\frac{1mmolCa(OH)_{2}}{2mmolHBr}$ = 0.6944 mmol Ca(OH)₂

Finally we calculate the molarity of the Ca(OH)₂ solution, using the given volume and calculated moles:

0.6944 mmol Ca(OH)₂ / 15.2 mL = 0.0457 M

7 0

2 years ago

A simplified version of the Periodic Table of the Elements is provided. What type of elements would you most likely find in the

vesna_86 [32]

Answer:

Transition elements are present in this region.

Explanation:

5 0

2 years ago